Equation
Let the number = x
(2/3)x + x = 20 Change the x to thirds.
(2/3)x + 3/3x = 20 3/3 = 1 Now combine the like terms.
(2 + 3)/3 = 20 2/3 + 3/3 = 5/3
(5/3) x = 20 Multiply both sides by 3/5
(5/3)*(3/5)x = 20*3/5 Complete the multiplication on the right
x = 4 * 3 Combine
x = 12 Answer
18x-8x2=0
Two solutions were found :
x = 9/4 = 2.250
x = 0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
18x - 23x2 = 0
Answer:
The roots of the polynomial are;
3 + 2i
and 3-2i
Step-by-step explanation:
Here, we want to solve the given polynomial using the completing the square method
We start by dividing through by 8
This will give;
x^2 - 6x = -13
To complete the square, we simply divide the coefficient of x by 2 and square it
We have this as -6/2 = -3
square it;; = (-3)^2 = 9
Add it to both sides
x^2 - 6x + 9 = -13 + 9
x^2 - 6x + 9 = -4
(x-3)^2 = -4
Find the square root of both sides
x-3 = ±2i
x = 3 + 2i
or x = 3-2i
The answer is 0.73 hope it helps
