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Lisa [10]
3 years ago
10

8x-2(xx9)=x+47. solve for x

Mathematics
1 answer:
Dafna11 [192]3 years ago
6 0
18x-8x2=0

Two solutions were found :

x = 9/4 = 2.250
x = 0
Step by step solution :

Step 1 :

Equation at the end of step 1 :

18x - 23x2 = 0
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m=2

Step-by-step explanation:

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What value of x is in the solution set of 4x - 12 s 16 + 8x?<br> 6 Of<br> -10<br> -7
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Your answer is (D)-7

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A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. if th
Oxana [17]
1 revolution of a circle = circumference of that circle.

<span>1 revolution of a circle with the diameter of 28 inches = </span><span><span>πd=28π</span><span>πd=28π</span></span><span> inches. Hence, x revolutions per second = </span><span><span>28πx</span><span>28πx</span></span><span> inches per second = </span><span><span>60∗28πx</span><span>60∗28πx</span></span><span> inches </span>per minute.

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7 0
3 years ago
Three years ago, Claire borrowed money from her father to pay for a class trip. She agreed to pay 6% simple annual interest on t
Nadya [2.5K]

Answer:

Claire borrowed $500 from her father.

Step-by-step explanation:

Interest = $90

p = ?

r = 6% or 0.06

t = 3

Simple interest formula is :

I=p\times r\times t

Putting values in formula we get;

90=p\times0.06\times3

90=0.18p

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Hence, Claire borrowed $500 from her father.

3 0
3 years ago
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If $5200 is invested at a rate of 8.6% compounded quarterly, how long will it take, to the nearest hundredth of a year, until th
dexar [7]

Answer:

t= 9.43\ years

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=?\ years\\ P=\$5,200\\ r=8.6\%=8.6\100=0.086\\n=4\\A=\$11,600  

substitute in the formula above

11,600=5,200(1+\frac{0.086}{4})^{4t}  

11,600=5,200(1.0215)^{4t}  

(11,600/5,200)=(1.0215)^{4t}  

Applying log both sides

log(11,600/5,200)=log(1.0215)^{4t}  

applying property of logarithms

log(11,600/5,200)=(4t)log(1.0215)  

t=log(11,600/5,200)/[(4)log(1.0215)]

t= 9.43\ years

5 0
3 years ago
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