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Masja [62]
3 years ago
9

Find the length of arc ac in terms of pi

Mathematics
1 answer:
aniked [119]3 years ago
3 0
=theta/360°×2pi ×r
theta=180-60=120°
r=24÷2=12

120/360 × 2 × 22/7 × 12=
1/3 × 2 × 22/7 × 12=
176/7=
25.14


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Vong grilled 21 burgers. He grilled the same number of pounds of turkey burgers as burgers. Turkey burger weighed 1/4 pound and
d1i1m1o1n [39]

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12 turkey burgers 9 hamburgers

Step-by-step explanation:

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3 years ago
The cost for taking a taxi is $1.80 plus $0.10 per eighth of a mile. What is the cost of a ride that is 4.5 miles long?
Sergio039 [100]

Answer:

$1.80 + (8x$0.10)*4.5 = $5.40

Step-by-step explanation:

$1.80 base cost

$0.10 for an 8th of a mile, thus multiply by 8 = $0.80 per mile

So, $1.80 + (4.5 * $0.8) = $5.40

7 0
3 years ago
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Look at the images please I WILL MRK THE BRIANLEST
professor190 [17]

Answer: V=234\ yd^3

Step-by-step explanation:

By definition, the volume of a rectangular prism can be calculated with the following formula:

V=lwh

Where "l" is the length, "w" is the width and "h" is the height of the rectangular prism.

In this case, you can identify that the length, the width and the height of this rectangular prism given in the exercise, are:

l=13\ yd\\\\w=6\ yd\\\\h=3\ yd

Then, knowing its dimensions, you can substitute them into the formula:

V=(13\ yd)(6\ yd)(3\ yd)

Finally, evaluating, you get that the volume of that rectangular prism is:

V=234\ yd^3

8 0
3 years ago
What is the solution to this system of linear equations?​
gregori [183]

Answer:

(-2,1)

Step-by-step explanation:

Just identify what point on the graph the lines intersect.

4 0
3 years ago
Changes in airport procedures require considerable planning. Arrival rates of aircrft are important factors that muct be taken i
Irina18 [472]

Answer:

a) 0.1558

b) 0.7983

c) 0.1478

Step-by-step explanation:

If we suppose that small aircraft arrive at the airport according to a <em>Poisson process</em> <em>at the rate of 5.5 per hour</em>  and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:

\bf P(X=k)=\displaystyle\frac{(5.5)^ke^{-5.5}}{k!}

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

\bf P(X=4)=\displaystyle\frac{(5.5)^4e^{-5.5}}{4!}=0.1558

(b) What is the probability that at least 4 arrive during a 1-hour period?

\bf P(X\geq4)=1-P(X

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?

If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now

\bf P(X=k)=\displaystyle\frac{(66)^ke^{-66}}{k!}

and we want <em>P(X ≥ 75) = 1-P(X<75)</em>. But

\bf P(X

hence

P(X ≥ 75) = 1-0.852 = 0.1478

7 0
3 years ago
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