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3 years ago

Roger expressed 1/5% as 1/500. Ellen expressed 1/5% as 100/5. Who is correct? Explain.

Mathematics

1 answer:

Scrat [10]3 years ago

3 0

Answer:

Ellen is correct

Step-by-step explanation:

Roger:

The left side 20 does not equal to the right side 0.002 , which means that the given statement is false.

Ellen:

The left side 20 is equal to the right side 20, which means that the given statement is always true.

Hope I helped, Brainliest would be appreciated :)

Have a fantastic day!

-Aadi x

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Parallelogram ABCD is a rectangle.

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5y - 2 = 4y + 1
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4 years ago

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Part of the student's solution for finding the quotient 288 ÷ 24 is shown below. 240 ÷ 24 = 10 288 – 240 = 48 48 ÷ 24 = 2 Which

Neporo4naja [7]

Answer:

A. 10 + 2

Step-by-step explanation:

288 ÷ 24 is shown below. 240 ÷ 24 = 10 288 – 240 = 48 48 ÷ 24 = 2

After obtaining the quotient of 288 ÷ 24 = 10,

Multiplying the divisor 24 by 10 = 240 and subtracting 240 from 288 to obtain the remainder = 48, the divisor is again used in 48 and the quotient obtained is added to the intula quotient value of 10 ; (10 + 2) and the process repeated

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3 years ago

The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?

Sliva [168]

Answer:

$A=15\pi\ units^2$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

$A=\pi r^{2}$

step 1

Find the Area of the 1st red circle

$r=2/2=1\ unit$ ---> the radius is half the diameter

$A_1=\pi (1)^{2}=\pi\ units^2$

step 2

Find the Area of the 2nd white circle

$r=4/2=2\ units$ ---> the radius is half the diameter

$A_2=\pi (2)^{2}=4\pi\ units^2$

step 3

Find the Area of the 3rd red circle

$r=6/2=3\ units$ ---> the radius is half the diameter

$A_3=\pi (3)^{2}=9\pi\ units^2$

step 4

Find the Area of the 4th white circle

$r=8/2=4\ units$ ---> the radius is half the diameter

$A_4=\pi (4)^{2}=16\pi\ units^2$

step 5

Find the Area of the 5th red circle

$r=10/2=5\ units$ ---> the radius is half the diameter

$A_5=\pi (5)^{2}=25\pi\ units^2$

The total red area is given by

$A=A_5-A_4+A_3-A_2+A_1$

substitute

$A=25\pi-16\pi+9\pi-4\pi+\pi$

$A=15\pi\ units^2$

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