1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
asambeis [7]
3 years ago
9

The equation that I typed in is right.

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

The answer to your question is

Step-by-step explanation:

Data

Point (2, 3)

line     y - 4 = -2(x + 3)

Process

1.- Solve for y the line given

          y - 4 = -2(x + 3)

          y - 4 = -2x - 6

           y = -2x - 6 + 4

           y = -2x - 2

2.- Get the slope of the new line

slope = 1/2

3.- Get the equation of the new line

           y - y1 = m(x - x1)

           y - 3 = 1/2(x - 2)

           y - 3 = 1/2x - 1

           y = 1/2x - 1 + 3

          y = 1/2x + 2

4.- Get the coordinates of the new line

When x = 0

           y = 1/2(0) + 2

           y = 2                 P (0, 2)

When y = 0

           0 = 1/2x + 2

           1/2x = -2

             x = -4              Q (-4, 0)

5.- Get the coordinates of the previous line

             y = -2x - 2

When x = 0

             y = -2(0) -2

             y = -2            R (0, -2)

When y = 0

            0 = -2x - 2

            -2x = 2

               x = 2/-2

               x = -1           S (-1, 0)

You might be interested in
PWEASE HELPPPPP
AveGali [126]

Answer:

For the length I think you meant 32, and if you did it is $14.40

If not and you meant length of 2 it is $0.90

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME QUICK!!!20 POINTS!!!!!!!!
Blizzard [7]

the volume scales by (1/10)^3. so it would be 48.875*10^-3.

5 0
3 years ago
If 96 students are going on a field trip 12 chaperones are needed how many chaperones are needed we f 125 students are going on
Musya8 [376]

Answer:

4500

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The value of y varies directly with x. When y=55, x=1/4. Determine the constant of proportionality
docker41 [41]

Answer:

<u>k = 220</u>

Step-by-step explanation:

<u>Proportion of y and x</u>

  • y = kx

<u>Given</u> :

  • y = 55
  • x = 1/4

<u>Solving</u> :

  • 55 = k/4
  • k = 55 x 4
  • <u>k = 220</u>
4 0
2 years ago
F(x) = x^2-3<br> What is the average rate of change on the interval [-5, 2] ?
Mumz [18]

Answer:

(-3).

Step-by-step explanation:

Over this interval, the change in the value of this function is:

f(-5) - f(2) = 22 - 1 = 21.

The corresponding change in the value of x:

(-5) - 2 = -7.

The average rate of change of function f over this interval is equal to the change in the function value divided by the corresponding change in x:

\begin{aligned}& (\text{average rate of change}) \\ =\; & \frac{(\text{change in function value})}{(\text{change in $x$})} \\ =\; & \frac{f(-5) - f(2)}{(-5) - 2} \\ =\; & \frac{22 - 1}{-7} \\ =\; & \frac{21}{-7} \\ =\; & -3\end{aligned}.

Thus, the average rate of change of f(x) = x^{2} - 3 over the interval [-5,\, 2] would be (-3).

7 0
2 years ago
Other questions:
  • For every left handed person, there are about 4 right-handed people. If there are 30 students in a class, predict the number of
    6·2 answers
  • Thanks for your help
    11·1 answer
  • What is the median of the following set of data?<br><br> 19, 45, 62, 5, 23, 45, 98, 11
    7·2 answers
  • What's the slope of the line shown in the picture?
    11·2 answers
  • How to round 9,381 to the nearest hundred
    6·2 answers
  • SOMEONE PLEASE HELP ME WITH THIS!!!!! ITS GEOMETRY
    14·1 answer
  • Let Q(x, y) be the predicate "If x &lt; y then x2 &lt; y2," with domain for both x and y being R, the set of all real numbers.
    12·1 answer
  • Resolver utilizando la regla de clamer
    14·1 answer
  • Geometry Help!
    13·1 answer
  • What's the square root of 25 in **simplest radical form**
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!