Question

Meg is a veterinarian. In a given week, 50% of

Answer 1

Answer:

• a. Meg needs to find the part

• b. Steve needs to find the percent.

Step-by-step explanation:

The question is incomplete.

This is the complete question:

Meg is a veterinarian. In a given week, 50% of the 16 dogs she saw were Boxers. Steve is also a veterinarian. In the same week, 7 of the 35 dogs he saw this week were Boxers. Each wants to record the part the whole, and the percent.

a. Does Meg need to find the part, the whole, or the percent.

b. Does Steve need to find the part, the whole, or the percent.

Solution to the problem

a. Does Meg need to find the part, the whole, or the percent.

Meg already knows the whole and the percent.

The whole is the entire number of dogs seen: 16 dogs.

The percent is 50%.

Hence, she needs to find the part: this is how many (what part) of the 16 dogs she saw were boxers.

And she can do with a simple operation:

• Part = whole × percent = 16 × 50% = 8. This is 8 dogs of 16 were boxers.

b. Does Steve need to find the part, the whole, or the percent.

He already knows the part (7 of the 35 dogs were boxers) and the whole (35 dogs).

Then he needs to find the percent, which he can do using the next operation:

• Percent = (part / whole) × 100 = (7/35)×100 = 20%