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Inessa05 [86]
3 years ago
7

Meg is a veterinarian. In a given week, 50% of

Mathematics
1 answer:
krek1111 [17]3 years ago
6 0

Answer:

<u><em></em></u>

  • <u><em>a. Meg needs to find the part</em></u>

<u><em></em></u>

  • <u><em>b. Steve needs to find the percent.</em></u>

<u><em></em></u>

Step-by-step explanation:

The question is incomplete.

This is the complete question:

<em>Meg is a veterinarian. In a given week, 50% of the 16 dogs she saw were Boxers. Steve is also a veterinarian. In the same week, 7 of the 35 dogs he saw this week were Boxers. Each wants to record the part the whole, and the percent.</em>

<em />

<em>a. Does Meg need to find the part, the whole, or the percent.</em>

<em />

<em>b. Does Steve need to find the part, the whole, or the percent.</em>

<em />

<h2>Solution to the problem</h2>

<u><em>a. Does Meg need to find the part, the whole, or the percent.</em></u>

<em />

<em>Meg</em> already knows the <em>whole</em> and the <em>percent</em>.

The whole is the entire number of dogs seen: <em>16 dog</em>s.

The percent is <em>50%.</em>

Hence, she needs to find the part: this is how many (what part) of the 16 dogs she saw were boxers.

And she can do with a simple operation:

  • Part = whole × percent = 16 × 50% = 8. This is 8 dogs of 16 were boxers.

<u>b. Does Steve need to find the part, the whole, or the percent.</u>

<u></u>

He already knows <em>the part</em> (<em>7 of the 35 dogs were boxers</em>) and <em>the whole </em>(<em>35 dogs</em>).

Then he needs to find the percent, which he can do using the next operation:

  • Percent = (part / whole) × 100 = (7/35)×100 = 20%
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Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

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To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = 5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}

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