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Setler79 [48]
4 years ago
15

A pilot flew his plane 225 miles in 45 minties

Mathematics
1 answer:
gtnhenbr [62]4 years ago
5 0
I don't get it it doesn't make sense
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Find the slope of the line that passes through the pair of points A(2,5) B(3,1)
nata0808 [166]

Answer:

The slope is -4

Step-by-step explanation:

slope = (y2-y1)/(x2-x1)

(1-5)/(3-2)

-4/1

-4

5 0
3 years ago
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PLEASE HELP!!!!!!!!!!!!
katovenus [111]
Let me ask my brother he's smart
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3 years ago
The perimeter of the figure below is 107.5 in. Find the length of the missing side
RideAnS [48]

9514 1404 393

Answer:

  7.3 in

Step-by-step explanation:

The sum of the lengths of the sides shown is 100.2 in, so the missing length is ...

  107.5 -100.2 = 7.3 . . . inches

8 0
4 years ago
Find 18% of 14. Use a decimal.<br><br> 25.2<br> 2.52<br> 0.32<br> 14.18
svetlana [45]
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8 0
3 years ago
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Insert geometric means in each geometric sequence.
Digiron [165]

Answer:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the n^{th} term of a geometric sequence.

a_n=ar^{n-1}

Where a is the first term and

r is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

ar = 24\\ar^4 = \dfrac{3}{64}

Solving the above equation:

r = \dfrac{1}{8}

Therefore, the sequence is:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

Considering the second given sequence:

ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2

Therefore, the sequence is:

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

Considering the third sequence:

a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3

Therefore, the sequence is:

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

5 0
3 years ago
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