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3 years ago

10

If 5,x,y,40 are in geometrical progression, find x and y respectively.

1 answer:

Andrei [34K]3 years ago

5 0

Answer:

x = 10, y = 20

Step-by-step explanation:

Because this is a geometric sequence, we'll call the rate of change z. Because 40 is 3 terms away from 5, we can write 5 * z * z * z = 5z³ = 40.

z³ = 8 → z = 2

Now, we simply multiply 5 by 2 to get x, which is 10, and then we multiply x by 2 to get 10 * 2 = 20 for y. Hope this helps!

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Please help me with this question im too slow to answer

kakasveta [241]

Answer:

92

Step-by-step explanation:

w=7

x=4

y=8

z=1

8^2 + 2(4) + 3 (7) -1

64 + 2 * 4 + 3 * 7 -1

64 + 8 + 21 - 1

72 + 20

92

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3 years ago

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Louise, Tammy, Delores, and Sheryl score 78 points total in the tennis matches they play. They score a consecutive number of poi

irga5000 [103]

$\huge\boxed{18\ \text{points}}$

We'll represent Louise's, Tammy's, Delores's, and Sheryl's point values with $x$ , $x+1$ , $x+2$ , and $x+3$ respectively since each one is 1 point more than the last.

Add all of these values up and set it all equal to $78$ .

$x+x+1+x+2+x+3=78$

Now, simplify.

$4x+6=78$

Subtract $6$ on both sides.

$\begin{aligned}4x+6-6&=78-6\\4x&=72\end{aligned}$

Divide both sides by $4$ .

$\begin{aligned}\frac{4x}{4}&=\frac{72}{4}\\x&=\boxed{18}\end{aligned}$

Since Louise's score is $x$ , the answer is $18$ .

<h3>Double-checking</h3>

To verify our answer, add the point totals $18$ , $19$ , $20$ , and $21$ .

This equals $78$ , so we can be sure the answer is correct.

5 0

1 year ago

Amber determined that the expression -1/2 divided by -41/15 is equivalent to 15/82. Which statement describes the process Amber

ddd [48]

Amber could have used cross multiplication.

Have a great day!!!!

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3 years ago

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mickel and 4 friend bought a total of 95 raffle tickets if the ticket were dived equaly among themselves how many tickets did ea

Simora [160]

Answer:

19

Step-by-step explanation:

5 people in total, divide equally from 95

4 0

3 years ago

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Compute the surface area of the portion of the sphere with center the origin and radius 4 that lies inside the cylinder x^2+y^2=

Tom [10]

Answer:

16π

Step-by-step explanation:

Given that:

The sphere of the radius = $x^2 + y^2 +z^2 = 4^2$

$z^2 = 16 -x^2 -y^2$

$z = \sqrt{16-x^2-y^2}$

The partial derivatives of $Z_x = \dfrac{-2x}{2 \sqrt{16-x^2 -y^2}}$

$Z_x = \dfrac{-x}{\sqrt{16-x^2 -y^2}}$

Similarly;

$Z_y = \dfrac{-y}{\sqrt{16-x^2 -y^2}}$

∴

$dS = \sqrt{1 + Z_x^2 +Z_y^2} \ \ . dA$

$=\sqrt{1 + \dfrac{x^2}{16-x^2-y^2} + \dfrac{y^2}{16-x^2-y^2} }\ \ .dA$

$=\sqrt{ \dfrac{16}{16-x^2-y^2} }\ \ .dA$

$=\dfrac{4}{\sqrt{ 16-x^2-y^2} }\ \ .dA$

Now; the region R = x² + y² = 12

Let;

x = rcosθ = x; x varies from 0 to 2π

y = rsinθ = y; y varies from 0 to $\sqrt{12}$

dA = rdrdθ

∴

The surface area $S = \int \limits _R \int \ dS$

$= \int \limits _R\int \ \dfrac{4}{\sqrt{ 16-x^2 -y^2} } \ dA$

$= \int \limits^{2 \pi}_{0} } \int^{\sqrt{12}}_{0} \dfrac{4}{\sqrt{16-r^2}} \ \ rdrd \theta$

$= 2 \pi \int^{\sqrt{12}}_{0} \ \dfrac{4r}{\sqrt{16-r^2}}\ dr$

$= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}$

$= 8\pi ( - \sqrt{4} + \sqrt{16})$

= 8π ( -2 + 4)

= 8π(2)

= 16π

4 0

3 years ago