Answer:
12m^-8
or you can write 12/m^8 it is the same
Step-by-step explanation:
Let's to the denominator first
(m^4 n^-2)^3 * (m^-4 n^2)^-2
since (a^b)^c = a^bc
we can rewrite the second factor as
(m^4 n^-2)^2 I have done this to simply remove the -4 and 2 exponents and make them 4 and -2 as in the first factor
at this point you have the same quantities between brackets () and you can multiply, considering that a^b * a^c = a^(b+c)
so the denominator becomes (m^4 n^-2)^5
at this point I would simply use the exponents
(12m^6 n^-5)^2 / (m^4 n^-2)^5 = (12m^12 n^-10) / (m^20 n^-10)
therefore, simplifying the similar factors
12m^-8
