D!
One clue to this (if you don’t just multiply 0.22 by 2.95) Is that this is the only value above 1. since the ending equation has a number larger than the original, this is a give away! Hope this helps :)
Answer:
28.57%
Step-by-step explanation
I added all the animals together and got the precentage of rabbits
Hopefully its right :)
Answer:
Simplify inside the parentheses by dividing coefficients, subtracting the exponents on like bases, and raising the resulting expression to the –3 power. Then, write bases with positive exponents.
Raise the numerator and denominator to the –3 power. Then, using the power of a power property, multiply the exponents. Divide the coefficients and subtract the exponents on like bases, then write with positive exponents.
Step-by-step explanation:
*see attachment for the diagram
Answer:
A. 178 units²
Step-by-step explanation:
Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)
✔️Surface area of the square pyramid = s² + 2*s*l
Where,
s = side length of square base (w) = 6 units
l = slant height = ?
Use Pythagorean theorem to find l
l = √((w/2)² + y²)
l = √((6/2)² + 5²) = √(9 + 25)
l = √34
l ≈ 5.8 units
Surface area of the square pyramid = 6² + 2*6*5.8 = 105.6 units²
✔️Surface area of square prism:
SA = 2a² + 4ah
Where,
a = w = 6 units
h = x = 3 units
Substitute
SA = 2(6²) + 4*6*3
= 72 + 72
= 144 units²
✔️base area of the square pyramid = s²
s = w
Base area = 6²
Base area = 36 units²
✅Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)
Surface area of the figure = (105.6 + 144) - 2(36)
= 249.6 - 72
= 177.6
≈ 178 units²
Answer:
Options are missing.
The options for the above question are:
TS.1: Linear in parameters.
TS.2:No perfect collinearity
TS.3: Zero conditional mean.
TS.4: Homoskedasticity.
TS.5: No serial correlation
TS.6: Normality.
Hence the correct answer is TS1 to TS 5
Step-by-step explanation:
Assumptions TS 1 to TS 5 are the minimum set of assumptions needed to for the OLS estimates to be the best linear unbiased estimators conditional on explanatory variables for all time periods.
The assumptions of Normality is not needed for the estimators to show the BLUE property
