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alexgriva [62]
3 years ago
6

Plz answer 1,2, and 3 for 28 points and BRAINLIEST ANSWER!!! Answer quickly!!!

Mathematics
2 answers:
drek231 [11]3 years ago
3 0
#1: b
#2: c
#3: d
#4: c
..... HOPE THIS HELPS!
Anna11 [10]3 years ago
3 0
#1: b#2: c#3: d#4: c
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Suppose the sound wave has the form y=7cos(3x-pi/6) for x in the interval [pi/6 , 7pi/18]. Express x as a function of y, and sta
Vesnalui [34]

Answer:

x = ⅓ acos(y/7) + π/18, [-7, 7/2]

Step-by-step explanation:

y = 7 cos(3x − π/6)

Solving for x:

y/7 = cos(3x − π/6)

acos(y/7) = 3x − π/6

acos(y/7) + π/6 = 3x

x = ⅓ acos(y/7) + π/18

The domain of x is the same as the range of y.

When x = π/6:

y = 7 cos(3π/6 − π/6)

y = 7 cos(π/3)

y = 7/2

When x = 7π/18:

y = 7 cos(21π/18 − π/6)

y = 7 cos(π)

y = -7

So the domain of x as a function of y is [-7, 7/2].

5 0
4 years ago
What is the answer to this question ? Please answer !!
mylen [45]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ k:y=m_2x+b_2,\ \text{then}\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\-------------------------\\\text{We have}\ 5x-y=-4.\ \text{Convert it to the slope-intercept form:}\\\\5x-y=-4\qquad\text{subtract 5x from both sides}\\\\-y=-5x-4\qquad\text{change the signs}\\\\y=5x+4\to m_1=5\to m_2=-\dfrac{1}{5}\\\\\text{Therefore we have}\ y=-\dfrac{1}{5}x+b.\\\\\text{The line passing through the point (-2, 2).}\\\text{Put the coordinates of the point to the equation:}

2=-\dfrac{1}{5}(-2)+b\\\\2=\dfrac{2}{5}+b\qquad\text{subtract}\ \dfrac{2}{5}\ \text{from both sides}\\\\1\dfrac{3}{5}=b\to b=\dfrac{8}{5}\\\\\text{Therefore we have the equation of a line in slope-intercept form:}\\\\y=-\dfrac{1}{5}x+\dfrac{8}{5}\\\\\text{Convert it to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{5}x+\dfrac{8}{5}\qquad\text{multiply both sides by 5}\\\\5y=-x+8\qquad\text{add x to both sides}\\\\\boxed{x+5y=8}\to\boxed{[B]}

8 0
3 years ago
An ectopic pregnancy is twice as likely to develop when the pregnant woman is a smoker as it iswhen she is a nonsmoker. If 32 pe
Dmitriy789 [7]

Answer:

48.48%

Step-by-step explanation:

Let's assume that there is a number N of women.

32% of these are smokers, then there are 0.32*N smokers

then 68% of these are non-smokers, then there are 0.68*N non-smokers.

Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)

Then the number of women with an ectopic pregnancy that are non-smokers is:

p*0.68*N

The number of women with an ectopic pregnancy that are smokers is:

2*p*0.32*N

Then the total number of women with an ectopic pregnancy will be:

p*0.68*N + 2*p*0.32*N

The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.

The percentage is:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\%

Taking p and N as common factors, we get:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\% = \frac{N*p}{N*p} \frac{2*0.32}{0.68 + 2*0.32} *100\%

Then we get:

\frac{2*0.32}{0.68 + 2*0.32} *100\% = 48.48\%

8 0
3 years ago
Jose paid $36.40 for 4 movie tickets. Each ticket costs the same amount. What was the cost of the movie tickets in dollars and c
Keith_Richards [23]

Answer:

$9.10

Step-by-step explanation:

Jose paid $36.40 <em>in total </em> for 4 movie tickets.

Divide $36.40 with 4

36.40/4 = 9.1

$9.10 is the cost of one movie ticket.

~

7 0
3 years ago
Pls help me this pls
Sunny_sXe [5.5K]

Answer:

RGDF

RGDF

Step-by-step explanation:

rgdf

rgdf

RGDF

7 0
3 years ago
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