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erik [133]
3 years ago
6

A test driver has to drive a car on a 1-mile track for two rounds in a way, that his average speed is 60 mph. On his first round

his average speed is 40 mph. How fast does he need to drive, to get the right speed average?
Mathematics
1 answer:
Volgvan3 years ago
3 0

to average 60 mph for 2 laps his total speed needs to equal 60 x 2 = 120

his first lap was 40 so his 2nd lap needs to be 120-40 = 80 mph

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4 years ago
Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated
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Well, I'm way past the 15 min mark, but here's how to do the question.


With this, you will need to use the distance formula, \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, on XY, YZ, and ZX.



XY: \sqrt{(3-1)^2+(1-6)^2}


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Next, solve the exponents: \sqrt{4+25}


Next, solve the addition, and XY's distance will be √29



(The process is the same with the other 2 sides, so I'll go through them real quickly)


YZ:

\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}



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\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}



Now that we got the 3 sides, we can add them up: \sqrt{29}+\sqrt{13} +\sqrt{34} =14.8


In short, your answer is 14.8, or the second option.

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