The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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(5,4)
x=5
y=4
hope this helped
mark brainliest :)
you question did not make sense so i assumed this is what you meant and needed.
Answer:
Triangle A: 38 degrees
Triangle B: Unknown (not enough information)
Triangle C: Unknown (not enough information)
Triangle D: 70 degrees
Triangle E: 40 degrees
Step-by-step explanation:
Work for Triangle A: 90 + 52 = 142. 180 - 142 = 38.
Work for Triangle B: Unidentifiable because there is no indicator to tell you if any of the angles/lines are equal. Generally there will be a "double lined" indicator in the corners of which a triangles angles are equal.
Work for Triangle C: Same as B.
Work for Triangle D: 90 + 20 = 110. 180 - 110 = 70.
Work for Triangle E: 90 + 50 = 140. 180 - 140 = 40.
This would just look like a bar graph.
On the horizontal axis, put your 4 different categories of 2, 3, 4, or 5.
On the vertical axis, label it by the percents: 0.10, 0.20, 0.30, 0.40
Then, make a bar at the correct height for each category.
We have that
2x²=450 ----------> x²=450/2----------> x=√225
x1=+15
x2=-15
<span>a reasonable length measurement should be positive
</span>therefore
the answer is
<span>The solutions are -15 and 15, but only 15 is a reasonable side length.</span>
