I am not sure on this question can someone please explain and solve for me ASAP

Mathematics

1 answer:

garik1379 [7]3 years ago

4 0

We have proportion:

$\dfrac{|JN|}{|JM|}=\dfrac{|LN|}{|MK|}$

We have:

$|JM|=8;\ |MK|=40;\ |LN|=30$

substitute:

$\dfrac{|JN|}{8}=\dfrac{30}{40}\ \ \ |\cdot8\\\\|JN|=\dfrac{30}{5}\\\\|JN|=6$

Answer: 6

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dezoksy [38]

Answer:

$\large\boxed{-\bigg[(x-3)^2+2x\bigg]+1}\\\\\boxed{-x^2+4x-8}$

Step-by-step explanation:

$(g\ \circ\ f)(x)=g\bigg(f(x)\bigg)$

$f(x)=(x-3)^2+2x\\\\g(x)=-x+1\\\\g\ \circ\ f\to\text{put f(x) instead of x in the function g(x)}:\\\\(g\ \circ\ f)(x)=-\bigg[\underbrace{(x-3)^2+2x}_{x}\bigg]+1$

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$-\bigg[(x-3)^2+2x\bigg]+1=-(x-3)^2-2x+1\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=-(x^2-(2)(x)(3)+3^2)-2x+1=-(x^2-6x+9)-2x+1\\\\=-x^2-(-6x)-9-2x+1=-x^2+6x-9-2x+1\\\\\text{combine like terms}\\\\=-x^2+(6x-2x)+(-9+1)=-x^2+4x-8$