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3 years ago

Plz help im almost done just a few more hw questions I'm stuck on

Mathematics

1 answer:

sesenic [268]3 years ago

8 0

The third one should be -2(2x-6)=12-4x
Last one should be 2(2x-6)+4x=8x-12

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Evaluate the expression: 6x + 5 - 3y, when y = 3 and x = -2

frozen [14]

First you need to substitute x for -2 and y for 3 in the equation.
So it would be...
6(-2) + 5 - 3(3)
-12+5-9
Then your answer is -16.
Hope that helped!

7 0

3 years ago

This is rlly easy but im just to lazy to answer it help pls ty

tankabanditka [31]

Answer:

C. 72

Step-by-step explanation:

-3 x -2 = 6

6 x 3 = 18

18 x 4 = 72

4 0

3 years ago

Read 2 more answers

A lot of 100 semiconductor chips contains 15 that are defective. three chips are selected at random from the lot without replace

Alex787 [66]

D=event that chip selected is defective
d=event that chip selected is NOT defective

Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154

Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20

5 0

4 years ago

Question 1

kenny6666 [7]

The inequality is given by 20x + 25y ≤ 1100 and x + y > 50

<h3>What is an inequality?</h3>

An inequality is an expression that shows the non equal comparison of two or more numbers and variables.

Let y represent the number of soccer balls and x represent the number of volleyballs.

The coach can spend a maximum of $1,100, hence:

20x + 25y ≤ 1100

Also, The coach plans to order at least 50, hence:

x + y > 50

The inequality is given by 20x + 25y ≤ 1100 and x + y > 50

Find out more on inequality at: brainly.com/question/24372553

6 0

2 years ago

10 Pts <br> Multiplying fractions:<br><br> 5 1 <br> — x — = <br> 6 2

Flauer [41]

Multiply the numerators together. Multiply the denominators together. Then reduce if necessary.

$\dfrac{first~numerator}{first~denominator} \times \dfrac{second~numerator}{second~denominator} = \dfrac{(first~numerator)\times(second~numerator)}{(first~denominator)\times(second~denominator)}$

$\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}$

$\dfrac{5}{6} \times \dfrac{1}{2} = \dfrac{5 \times 1}{6 \times 2} = \dfrac{5}{12}$

6 0

4 years ago

Read 2 more answers