Answer:
x = -3, 
Step-by-step explanation:
The given quadratic equation is: 
This can be written as: 
To solve a quadratic equation of the form
we use the formula:

Here, a = 2; b = 3; c = - 9
Therefore, the roots of the equation are:



We get two values of 'x', viz.,
x =
and 

⇒ x = -3, 3/2
Since the factors of the quadratic equation is asked, we write it as:
(x + 3)(x -
) = 0
because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.
Multiply (x + 3) and (x -
to see that this indeed is the given quadratic equation.
Answer:
72 cm squared
Step-by-step explanation:
3 x 4 x 6 = 72 cm squared
Answer:

Step-by-step explanation:


<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>(</em><em>4</em><em>,</em><em>7</em><em>)</em>
<em>look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>