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The function that represents the number of E.coli bacteria cells per 100 mL of water as t years elapses, and is missing in the question, is:
Answer:
Option A. 59%
Explanation:
The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function::
Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.
You can calculate it also using two consecutive values for t. For instance, use t =1 and t = 1
You should be able to note that this is a parabola which opens downward. Taking the derivative and setting it to -0- will yield the max of the equation, That is
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