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Akimi4 [234]
3 years ago
9

Can a matrix of dimensions 2 X 4 be added to another matrix with dimensions of 2 X 6?

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

No.

Step-by-step explanation:

It has different order of matrices .

For <em>A</em><em>d</em><em>d</em><em>i</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>or <em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>, both matrices must have the same number of <u>r</u><u>o</u><u>w</u><u>s</u> and <u>c</u><u>o</u><u>l</u><u>u</u><u>m</u><u>n</u><u>s</u> .

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Pls help if your kind &lt;3 (picture)
AlladinOne [14]

Answer:

1: x=23.313708 2: B x = -13.2 3: x = 152

All the problems examples at the bottom

Step-by-step explanation:

1: 12x=−3(4−x)

12x=3x−12

Step 1: Divide both sides by 12.

12x12=3x−1212

x=14x−1

Step 2: Solve Square Root.

x=14x−1

x=(14x−1)2(Square both sides)

x=116x2+−12x+1

x−(116x2+−12x+1)=116x2+−12x+1−(116x2+−12x+1)(Subtract 1/16x^2+(-1)/2x+1 from both sides)

−116x2+32x−1=0

x=−b±b2−4ac2a(Use quadratic formula with a=-0.0625, b=1.5, c=-1)

x=−(1.5)±(1.5)2−4(−0.0625)(−1)2(−0.0625)

x=−1.5±2−0.125

x=0.6862915010152388,23.31370849898476

2: 3+2.7x=9.6+3.2x

Step 1: Simplify both sides of the equation.

2.7x+3=3.2x+9.6

Step 2: Subtract 3.2x from both sides.

2.7x+3−3.2x=3.2x+9.6−3.2x

−0.5x+3=9.6

Step 3: Subtract 3 from both sides.

−0.5x+3−3=9.6−3

−0.5x=6.6

Step 4: Divide both sides by -0.5.

−0.5x−0.5=6.6−0.5

x=−13.2

3: 9+34x=78x−10

Step 1: Simplify both sides of the equation.

9+34x=78x−10

9+34x=78x+−10

34x+9=78x−10

Step 2: Subtract 7/8x from both sides.

34x+9−78x=78x−10−78x

−18x+9=−10

Step 3: Subtract 9 from both sides.

−18x+9−9=−10−9

−18x=−19

Step 4: Multiply both sides by 8/(-1).

(8−1)*(−18x)=(8−1)*(−19)

x=152

I really hope this helped you

4 0
3 years ago
Lavel the vertex and axis of symmetry
Lostsunrise [7]
The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The xx -coordinate of the vertex is the equation of the axis of symmetry of the parabola.
3 0
3 years ago
Suppose we have a population that does not follow the normal distribution. What minimum sample size we should select in order to
Pepsi [2]

Answer:

D. 30

Step-by-step explanation:

Having a population that doesn't follow normal distribution (skewed) can still have sampling distribution that is completely normal. This fact is presented in the Central Limit Theorem.

Central Limit Theorem: states that we can have a normal distribution of sample means even if the original population doesn't follow normal distribution, we just need to take a large sample.

So how much sample size do we need?

There is no straight forward answer to this rather we have to analyse the situation closely!

1. If the population distribution is already normal then a smaller sample size would be enough to ensure normal distribution.

2. If the population distribution is very skewed than a larger number of sample size is needed to ensure normal distribution. The rule of thumb is to take sample size equal to or more than 30 to be on safer side. This is the case in this problem hence option D fits the best.

5 0
3 years ago
If the spherical water balloon is filled with 113 milliliters of water, what is the approximate radius of the balloon
ladessa [460]

Answer:

The approximate radius is 2.99914. Let me know if this helps you out!

Step-by-step explanation:


5 0
3 years ago
If tan theta= -3/4 and θ is in quadrant IV, cos2 theta= and tan2 theta= .
Oksanka [162]

\cos 2(\text { theta })=\frac{7}{25}

\tan 2(\text { theta })=-\frac{24}{7}

<u>Step-by-step explanation:</u>

Given data:

               \tan \theta=-\frac{3}{4}

To find:

           cos 2 theta and tan 2 theta

<u>Solution:</u>

Hence, the trigonometric  formula for those are below,

                    \tan 2(\text { theta })=\frac{2 \tan (\text { theta })}{1-\tan ^{2}(\text { theta })}

                    \cos 2(\text { theta })=\frac{1-\tan ^{2}(\text { theta })}{1+\tan ^{2}(\text { thet } a)}

Now, find the required data by substituting the given value. We get,

                    \tan 2(\text { theta })=\frac{2 \times\left(-\frac{3}{4}\right)}{1-\frac{9}{16}}=-\frac{3}{2} \times \frac{16}{7}=-\frac{24}{7}

Similarly for cos 2 theta,

                  \cos 2(\text { theta })=\frac{1-\frac{9}{16}}{1+\frac{9}{16}}=\frac{7}{16} \times \frac{16}{25}=\frac{7}{25}

3 0
3 years ago
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