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4 years ago

3^3 • 32 + 12 ÷ 4 a. 219 b. 291 c. 867 d. 437

Mathematics

1 answer:

Sliva [168]4 years ago

3 0

The answer is 867.

3^3 = 27

27•32 + 12/4
864 + 3 = 867

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Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

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Which values of x make the equation |x - 7| = x - 7 true? 9 0 3 8 -7

Vlad [161]

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I might not be right but that’s what I got.

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Given the following information, determine if one of the brands is a better buy. Brand A: 14 ounces for $44. 66 Brand B: 20 ounc

maksim [4K]

Division is one of the basic mathematical operations. The cost of Brand A and B is the same.

<h3>What is division?</h3>

The division is one of the most basic arithmetic operations. It is used to find the number of times a number is been added to itself.

Given to us

Brand A: 14 ounces for $44.66

Brand B: 20 ounces for $63.80

To compare the two brands we will find the cost of one ounce for each brand.

For Brand A,

The cost of 14 ounces is $44.66, therefore,

$\text{Cost of one ounce} = \dfrac{\$44.66}{14}\\\\\text{Cost of one ounce} = \$3.19$

For Brand B,

The cost of 20 ounces is $63.80, therefore,

$\text{Cost of one ounce} = \dfrac{\$63.80}{20}\\\\\text{Cost of one ounce} = \$3.19$

From the above two values, we can conclude that the cost of Brand A and B is the same.

Learn more about Division:

brainly.com/question/369266

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