Hello there! We are talking about 86 being part of a number, so we are looking for the whole. To find the number we are looking for, we can write and solve a proportion. Set it up like this:
86/x = 45/100
86 is 45% of a number. We know the part, so now we are looking for the whole. 45% is part of 100%, so we put that part together. Cross multiply the digits. 100 * 86 is 8,600. 45 * x is 45x. That simplifies to 8,600 = 45x. Now, divide each side by 45 to isolate the x. 45x/45 cancels out. 8,600/45 is 191.1111111 or 191 1/9 in fraction form. There. x = 191 1/9 86 is 45% or 191 1/9
Note: Or, if you have to round to the nearest whole number, the answer is 191, or if you have to round to the nearest tenth, the answer is 191.1. It all depends on if the answer needs to be rounded or exact.
Answer:
20
Step-by-step explanation:
Answer:
16
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
Leg <em>a</em> = <em>a</em>
Leg <em>b</em> = 12
Hypotenuse <em>c</em> = 20
<u>Step 2: Solve for </u><em><u>a</u></em>
- Substitute in variables [Pythagorean Theorem]: a² + 12² = 20²
- Evaluate exponents: a² + 144 = 400
- [Subtraction Property of Equality] Isolate <em>a</em> term: a² = 256
- [Equality Property] Square root both sides: a = 16
Answer:
12 teams
Step-by-step explanation:
We know that 38 players can fit into 4 groups, 8 times ...
32 divide 8 = 4
We have the number with 96, and we need to find the groups
we do the same as done with the first one...
because 32 divided by 8 is 4
we do
96 divide 8 = 12
aswell
<h2><u>
<em>hope this helped : )</em></u></h2>
