Given
A tea that is 22% jasmine is blended with a tea that is 13% jasmine
Find out the how many pounds of the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine.
To proof
Let us assume that the a tea that is 22% jasmine is blended = a
Let us assume that the a tea that is 13% jasmine is blended = b
Total amount of tea made = 10lb
the equation be
a + b = 10
as given
jasmine tea are used to make 10lb of tea that is 19.3% jasmine.
write 22% in the decimal form

= 0.22
write 13% in the decimal form

= 0.13
write 19.3% in the decimal form

= 0.193
than the equation be
0.22a + 0.13b = 0.193 × 10
on simplify
22a + 13b = 193
two equation becomes
22a + 13b = 193 and a + b = 10
multiply a + b = 10 by 13 and subtracted from the 22a + 13b = 193
we get
22a - 13a + 13b -13b = 193 - 130
9a = 63
a = 7lb
put this value in the a + b = 10
we get
7 + b = 10
b = 3lb
Therefore the 22% jasmine tea are used to make 10lb of tea that is 19.3% jasmine is 7 lb .
Hence proved
Answer:
2698
Step-by-step explanation:First you take 1000 from 5000 and then distribute it to 395
Answer:
56.52 is the circumference. If the radias is 9 and the diameter is then 18.
Step-by-step explanation:
Graph images undergo transformations, one of the types of transformations are rotations.
rotation is done when each point of the image rotates 90° around a point in the counterclockwise manner.
when rotation is done, (x,y) -> (-y,x)
therefore when taking points from image to original then the reverse is done ;
(-y,x) --> (x,y)
the coordinates of image point q' is (-3,4)
before rotation then the coordinates are (4,3)
answer is (4,3)
Answer:
Step-by-step explanation:
height h = 11 cm
slant height s = 11.180339887499 cm
side length a = 4 cm
lateral edge length e = 11.357816691601 cm
1/2 side length r = 2 cm
volume V = 58.666666666667 cm3
lateral surface area L = 89.442719099992 cm2
base surface area B = 16 cm2
total surface area A = 105.44271909999 cm2