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3 years ago

• Close the window with the Nearpod lesson to return to the rest of the lesson and cli

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

7 0

Answer:

we need to discuss that but first tell me are you in school for real?

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Mariulka [41]

Perimeter of the ΔJKL is 48 cm

Solution:

Given $\triangle \mathrm{RST} \sim \Delta \mathrm{JKL}$ .

RS = 8 cm and JK = 12 cm

Perimeter of $\triangle R S T$ = 32 cm

Let us find the perimeter of $\Delta J K L$ .

<u>Property of similarity triangles:</u>

If two triangles are similar, then the ratio of their perimeters is equal to the ratio of their corresponding sides.

$$\frac{\text{Perimeter of}\ \triangle RST }{{\text{Perimeter of}\ \triangle JKL}} =\frac{RS}{JK}$

$$\Rightarrow\frac{32 }{{\text{Perimeter of}\ \triangle JKL}} =\frac{8}{12}$

Do cross multiplication.

$$\Rightarrow 32\times 12 ={8}\times {\text{Perimeter of}\ \triangle JKL}$

$$\Rightarrow 384 ={8}\times {\text{Perimeter of}\ \triangle JKL}$

Divide both sides of the equation by 8.

$$\Rightarrow 48 = {\text{Perimeter of}\ \triangle JKL}$

Hence perimeter of the ΔJKL is 48 cm.

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4 years ago

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diamong [38]

Answer:

Step-by-step explanation:

You times 8/3 and 21/2 to get 28

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3 years ago

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m_a_m_a [10]

Answer:

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Step-by-step explanation:

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3 years ago

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Ludmilka [50]

The surface area of it is 164 because you multiply each side by the length of the height and width and then add them all together

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s344n2d4d5 [400]

Answer:

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this is my answers

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