Answer:
2.54 seconds
Step-by-step explanation:
We can use the following equation to model the vertical position of the ball:
S = So + Vo*t + a*t^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
Then, using S = 2.5, So = 0.4, Vo = 14 and a = -9.8 m/s2, we have that:
2.5 = 0.4 + 14*t - 4.9t^2
4.9t^2 - 14t + 2.1 = 0
Solving this quadratic equation, we have that t1 = 2.6983 s and t2 = 0.1588 s.
Between these times, the ball will be higher than 2.5 m, so the amount of time the ball will be higher than 2.5 m is:
t1 - t2 = 2.6983 - 0.1588 = 2.54 seconds
<span>Point slope form is (y - y1) = m(x - x1), where m is a slope of 2, and x1 = 0 and y1 = 0 are our point at the origin. Therefore, we can plug in these values to get the point slope equation for our line:
(y – 0) = 2*(x - 0)</span>
Multiply because it says the word "times" in it.
Answer:
x = 47
Step-by-step explanation:
So It most likely adds up to 180 degrees so.
x + 10 + x -10 + x - 10 + x + 6 = 180 (collect like terms)
4x -4 = 184 ( add 4 on both sides)
4x = 188 (divide 188 by 4)
x = 47
47 + 10 = 57 ----> x + 10
47 - 10 = 37 -----> x - 10
47 + 6 = 53 ------> x + 6
Answer:
x = 41
Step-by-step explanation:
We know these angles will be equal to each other (they are across from each other, I honestly forget the term ) so we can set up an equation
Our equation from given: 104 = 3x - 19
Adding 19 to both sides 123 = 3x
Dividing both sides by 3: 41 = x
Answer: x = 41
