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Oksana_A [137]
4 years ago
15

Brianne solved a quadratic equation. Her work is shown below, with Step 2 missing.

Mathematics
2 answers:
Alja [10]4 years ago
6 0

Given:

The given quadratic equation is

3(x+4)^{2} = 48

or, (x+4)^{2} =16

And

The roots are given: x = -8 , x = 0

To find the missing step.

Let us solve the equation.

3(x+4)^{2} = 48

or, (x+4)^{2} = 16

or, x^{2} +8x+16 = 16 [ eliminating 16 from both the side]

or, x^{2} +8x = 0

or, x(x+8) = 0

or, x = 0, x = -8

Hence,

The step 2 could be x^{2} +8x = 0

GalinKa [24]4 years ago
4 0

Answer:

C

Step-by-step explanation:

Pray!

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Answer:

Part A: 15

Part B:

Point slope form: y-400=15(x-5)

Slope intercept form: y =15x+325

Standard Form: 15x-y+325=0

Part C: g(x) =15x+325

Part D: 505

Step-by-step explanation:

We are given the following

x       g(x)

5      $400

10    $475

We can see that these are two points on the line.

i.e. (5, 400) and (10, 475)

OR

x_1 = 5\\x_2 = 10\\y_1 = 400\\y_2 = 475

<u>Part A: </u>Slope of the function:

m=\dfrac{y_2-y_1}{x_2-x_1} \\\Rightarrow m = \dfrac{475-400}{10-5}\\\Rightarrow m = \dfrac{75}{5} = 15

So, slope of the line = 15

<em>It has a positive slope and the function will be increasing with the increasing value of 'x'.</em>

<em></em>

<u>Part B:</u>

Point slope form of a line is given as:

y-y_1=m(x-x_1)

Putting (x_1, y_1)\ as\ (5, 400):

y-400=15(x-5)

Slope intercept form:

y=mx+c where c is the intercept.

y =15x+c

Putting (x,y) as (5, 400) to find c:

400=15\times5+c\\\Rightarrow c = 325

So, the equation in slope intercept form:

y =15x+325

Standard form of line:

Ax+By+C=0

Rewriting the slope intercept form:

15x-y+325=0

<u>Part C:</u>

Using the function notation, putting y = g(x) in slope intercept form:

g(x) =15x+325

<u>Part D:</u>

Balance after 12 days = ?

i.e. g(x) = ? at x = 12

Putting x = 12 in g(x) =15x+325

g(12) =15\times 12+325\\\Rightarrow g(12)=505

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