X+(x+1)+(x+2)+(x+3)=156
4x+6=156
4x=150
x=37.5 (not an integer)
If x=37 you get 37+38+39+40=154 and if x=38 you get 38+39+40+41=158[/tex]
Answer:
0, 1, 2
Step-by-step explanation:
So, since there are three consecutive integers, you have the equations
x, x+1, x+2 where x is the smallest number.
The greatest of the three integers= x+2
Finish setting up your equation;
2(x+x+1)=x+2
Combine like terms;
2(2x+1)=x+2
Distribute;
4x+2=x+2
3x=0
x=0
x+1=1
x+2=2
Hope this helps:) Have a good day!
Answer:
yes
Step-by-step explanation:
Answer:
The given sequence 6, 7, 13, 20, ... is a recursive sequence
Step-by-step explanation:
As the given sequence is

- It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.
As
, 
As d is not same. Hence, it cannot be an arithmetic sequence.
- It also cannot be a geometrical sequence and exponential sequence.
It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.
As
,
, 
As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.
So, if we carefully observe, we can determine that:
- The given sequence 6, 7, 13, 20, ... is a recursive sequence.
Please have a close look that each term is being created by adding the preceding two terms.
For example, the sequence is generated by starting from 1.

and

for n > 1.
<em>Keywords: sequence, arithmetic sequence, geometric sequence, exponential sequence</em>
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