What is +24 - negative 0.08%

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kobusy [5.1K]

Answer:

people liked online better

Step-by-step explanation:

8 0

3 years ago

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Solve and check. 1. d - 6 = 33 6-6

AVprozaik [17]

Start off by adding 33 + 6 which is 36 and so that’s how you find what d equals

3 0

3 years ago

PLZ HELP WILL GIVE BRAINILST IF CORECCT

Mashutka [201]

Answer:

5.00

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

HELP!! I NEED THIS QUICKLY

Elza [17]

Answer:

A and D

Step-by-step explanation:

We are given that

(3/4,2/3),(1/4,1),(1,1/2) and (1/2,1)

$x_1=\frac{3}{4}$

$y_1=\frac{2}{3}$

$x_2=\frac{1}{4},y_2=1$

$x_3=1,y_3=\frac{1}{2}$

$x_4=\frac{1}{2},y_4=1$

k= $\frac{1}{2}$

Direct proportion:

$\frac{x}{y}=k$

Inverse proportion: $xy=k$

$\frac{x_1}{y_1}=\frac{3}{4}\times \frac{3}{2}=\frac{9}{8}\neq \frac{1}{2}$

Therefore, it is not in direct proportion.

$\frac{1}{4\times 2}=\frac{1}{8}\neq\frac{1}{2}$

$\frac{1}{\frac{1}{2}}=2\neq \frac{1}{2}$

$x_1y_1=\frac{3}{4}\times \frac{2}{3}=\frac{1}{2}$

$x_2y_2=\frac{1}{4}\times 2=\frac{1}{2}$

$x_3y_3=1\times \frac{1}{2}=\frac{1}{2}$

$x_4y_4=\frac{1}{2}\times 1=\frac{1}{2}$

Therefore, $xy=k=\frac{1}{2}$

Hence, the given points form an inverse variation .

$xy=\frac{1}{2}$

$y=\frac{1}{2x}$

Option A and D is true.

6 0

3 years ago

Help? I can't seem to understand arithmegic sequence.

katrin2010 [14]

A sequence $\{a_n\}$ is arithmetic if the difference between consecutive terms is some fixed number, regardless of which pair of consecutive terms you pick out of the sequence.

For example, the following sequences are arithmetic:

1, 2, 3, 4, 5, 6, ... (difference = 1)

-25, -20, -15, -10, -5, ... (difference = 5)

2. Carla's sequence is not arithmetic, because the differences between consecutive terms are all different:

13 - 11 = 2

17 - 13 = 4

25 - 17 = 8

She can adjust the sequence by changing the last two numbers to 15 and 17, since this makes the difference fixed:

13 - 11 = 2

15 - 13 = 2

17 - 15 = 2

and so on.

3. The sequence

45, 48, 51, 54, ...

is arithmetic with difference 3 between terms. Recursively, we can write the $n$ th term, $a_n$ , in terms of the previous, $(n-1)$ th term, $a_{n-1}$ :

$a_n=a_{n-1}+3$

By this definition, we can just as easily write the $(n-1)$ th term in terms of the $(n-2)$ th term:

$a_{n-1}=a_{n-2}+3$

Then, substituting this into the previous equation, we have

$a_n=(a_{n-2}+3)+3=a_{n-2}+2\cdot3$

We can continue this process to write $a_n$ in terms of $a_1$ :

$a_{n-2}=a_{n-3}+3\implies a_n=a_{n-3}+3\cdot3$

$a_{n-3}=a_{n-4}+3\implies a_n=a_{n-4}+4\cdot3$

and so on. (You might notice that the subscript of the term on the right side, and the number of 3s being added, together sum to $n$ .) The pattern continues down to

$a_n=a_1+(n-1)\cdot3$