Least common multiple of 12,18and 4
2 answers:
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Answer:
x ≥ -1/2
Step-by-step explanation:
We know that we cannot graph imaginary numbers. Therefore, our <em>x </em>value has to be greater than or equal to 0:
To find our domain, we need to set the square root equal to zero:
√(4x + 2) = 0
4x + 2 = 0
4x = -2
x = -1/2
We now know that no value below -1/2 can be used or we will get an imaginary number. Therefore, our answer is x ≥ -1/2
Alternatively, we can graph the function and analyze domain:
Answer:
See explanation
Step-by-step explanation:
Assuming the given inequality is
Then the corresponding linear equation is
When x=0, we have
When y=0, we have
The T-table is:
<u>x | y</u>
0 | 4
6 | 12
We plot this points and draw a solid straight line as shown in the attachment.
Now let us test the origin: (0,0) by plugging x=0 and y=0 into the inequality.
....This is true so we shade the lower half plane as shown in the attachment.
