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4 years ago

Two positive numbers have a difference of 13. The larger number is three more than twice the smaller. Find the two numbers.

Mathematics

2 answers:

Y_Kistochka [10]4 years ago

4 0

Step-by-step explanation: Let x be the larger number and let y be the smaller one.

x-y=13

x=2y+3

Now you can substitute x=2y-3 into the first equation.

x-y=13=(2y+3)-y

y+3=13

y=10

x=2y+3=20+3=23. Hope that helped!

hammer [34]4 years ago

4 0

Answer:

$x = 23 \\ y = 10$

Step-by-step explanation:

$x - y = 13 = > y = x - 13\\ x = 2y + 3 \\ \\ x = 2(x - 13) + 3 \\ x = 2x - 23 \\ x = 23 \\ \\ 23 - y = 13 \\ 23 - 13 = y \\ y = 10$

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Answer:

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Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the uniform distribution is:

$M = \frac{a + b}{2}$

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The standard deviation is the square root of the variance.

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This means that $a = 1, b = 53$

a. The mean of this distribution is

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Through: (-5, -5), parallel to y = 3/5x + 3

Komok [63]

Answer:

$\displaystyle y=\frac{3}{5}x-2$

Step-by-step explanation:

We want to find the equation of a line parallel to:

$\displaystyle y=\frac{3}{5}x+3$

And passes through (-5, -5).

Recall that parallel lines must have the same slope.

Since the slope of our old line is 3/5, the slope of our new line must also be 3/5.

So, we know that the slope of our new line is 3/5 and it passes through (-5, -5).

Now, we can use the point-slope form given by:

$y-y_1=m(x-x_1)$

We will let (-5, -5) be (x₁, y₁). m is the slope or 3/5. Hence:

$\displaystyle y-(-5)=\frac{3}{5}(x-(-5))$

Simplify:

$\displaystyle y+5=\frac{3}{5}(x+5)$

Distribute:

$\displaystyle y+5=\frac{3}{5}x+3$

Subtract 5 from both sides:

$\displaystyle y=\frac{3}{5}x-2$

And we have our equation.

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3 years ago