Question

Two positive numbers have a difference of 13. The larger number is three more than twice the smaller. Find the two numbers.

Answer 1

Step-by-step explanation: Let x be the larger number and let y be the smaller one.

x-y=13

x=2y+3

Now you can substitute x=2y-3 into the first equation.

x-y=13=(2y+3)-y

y+3=13

y=10

x=2y+3=20+3=23. Hope that helped!

Answer 2

Answer:

$x = 23 \\ y = 10$

Step-by-step explanation:

$x - y = 13 = > y = x - 13\\ x = 2y + 3 \\ \\ x = 2(x - 13) + 3 \\ x = 2x - 23 \\ x = 23 \\ \\ 23 - y = 13 \\ 23 - 13 = y \\ y = 10$