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3 years ago

How many plants spaced every 5 in. are needed to surround a circular walkway with a 20-ft radius?

Mathematics

1 answer:

n200080 [17]3 years ago

8 0

Answer:

Step-by-step explanation:

if 1 ft is 12 in

transfer 20 ft in to in

and you get 240

then do 240 divided by 5

then you get your answer of 48

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The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.1

Ivan

Answer:

0.6 probability that $-2 \leq x \leq 2$

Step-by-step explanation:

The probability distribution is given in the table.

Probability that x is between -2 and 2.

Between -2 and 2, inclusive, we have -2, 0 and 2. So

$P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2)$

From the table:

$P(X = -2) = 0.33, P(X = 0) = 0.16, P(X = 2) = 0.11$ . So

$P(-2 \leq x \leq 2) = P(X = -2) + P(X = 0) + P(X = 2) = 0.33 + 0.16 + 0.11 = 0.60$

0.6 probability that $-2 \leq x \leq 2$

4 0

3 years ago

Part 3 - Discussion/Explanation Question

SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

$\frac{1}{x - 5}$

Set the expression in the denominator equal to 0, because you can't divide by 0.

$x - 5 = 0$

$x = 5$

So the vertical asymptote is x=5.

Disclaimer if you see something like this

$\frac{(x - 5)(x + 3)}{(x - 5)}$

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

$\frac{1}{x}$

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

$a \times {x}^{0}$

For example,

$1 = 1 \times {x}^{0}$

$2 = 2 \times {x}^{0}$

And so on,

and

$x = {x}^{1}$

So our equation is basically

$\frac{1 \times {x}^{0} }{ {x}^{1} }$

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

$\frac{3 {x}^{2} }{ {x}^{2} + 1}$

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

$x = \frac{3}{1}$

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0

2 years ago

A spherical balloon is inflated with a gas at the rate of 500 cm3/min. How fast is the radius of the balloon increasing at the i

Burka [1]

The volume of the sphere is expressed in the formula V = 4/3 pi r^3. The rate of change of volume is determined by differentiating the formula: dV/dt = 4pi r^2 dr/dt. When we substitute 500 cm3/min as dV/dt and 30 cm as r. Then dr/dt is equal to 0.0442 cm/min

7 0

4 years ago

In right triangle PQR, tanP =sqrt 3/2. Find the length of the hypotenuse of triangle PQR.

Aleksandr [31]

$\sqrt{ \sqrt{3}^2+2^2} = \sqrt{3+4} = \sqrt{7}$