Yes due to the fact that additive inverse is the oppsite. so she runs up +4 and runs down -4.
A square is a figure with four equal sides and four right angles.In a square the diagonals bisect at right angles .
In the above given options option A is the right answer.
If the diagonals of any parallelogram are perpendicular then the figure is not necessarily a square.
Diagonals are perpendicular in a rhombus too.
A square and Rhombus both have diagonals that are perpendicular.
So it is not a necessary condition for a parallelogram to be a square .
The other options are right .
So option B is the right option that if diagonals are perpendicular is not sufficient to prove the figure to be a square.
The answer is 7.58
hope this helped :)
alisa202
Angle between 16 and 18 = 90 + 55 = 145°
8xy-7xy-3xy-3y²-2y²+8y²+5x²+12x²
then simplify by combining like terms -2xy+3y²+17x²
