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antoniya [11.8K]
3 years ago
10

Number 2 I need help please?!!!!):

Mathematics
2 answers:
Lana71 [14]3 years ago
5 0

answer: y < 4

explanation: y < - 4 + 8

ivann1987 [24]3 years ago
4 0

Answer:

Step-by-step explanation:

y<4

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There are 3 consecutive numbers whose sum is equal to the result of their multiplication. Which are they?
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2 years ago
How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove
BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

\dfrac{9}{n^2+1} =\dfrac{n+3}{4}

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\

The roots (zeros) are the  x  values where the graph intersects the x-axis. To find the roots (zeros), replace  y

with  0  and solve for  x. The graph of the equation is attached.

n  ≈  2.38450287

Hence, The equation has one extraneous solution which is n  ≈  2.38450287

For more information refer to the link.

brainly.com/question/15070282

5 0
2 years ago
5x(6x+28)=-23 <br><br>Help I don't understand
aksik [14]

Answer:

Solve the equation for  x  by finding  a,  b, and  c  of the quadratic then applying the quadratic formula.


Exact Form:


x  =  −  70  ±  √4210/30


Decimal Form:


x  =  −0.03


Step-by-step explanation:

5x(6x+28)=−23


Step 1: Simplify both sides of the equation.


30x2+140x=−23


Step 2: Subtract -23 from both sides.


30x2+140x−(−23)=−23−(−23)


30x2+140x+23=0


Step 3: Use quadratic formula with a=30, b=140, c=23.


x=−b±√b2−4ac/2a


x=−(140)±√(140)2−4(30)(23)/2(30)


x=−140±√16840/60


x=−7/3+1/30√4210 or x=−7/3+−1/30√4210

3 0
3 years ago
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