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kherson [118]
3 years ago
15

Grace was driving down a road and after 4 hours she had traveled 66 miles. At this speed, how many miles could Grace travel in 8

hours?
Fill out the table of equivalent ratios until you have found the value of x.
Mathematics
2 answers:
umka2103 [35]3 years ago
6 0

Answer:

132 miles

Step-by-step explanation:

4 is half of 8 so you just have to multiple everything by 2 to get your answer

Sunny_sXe [5.5K]3 years ago
5 0

Answer:

132

Step-by-step explanation:

Since in four hours you can travel 66 miles, 8 hours would be 66x2, which is 132.

1hour=16.5

2hour=33

3hour=49.5

4hour=66

5hour=82.5

6hour=99

7hour=115.5

8hour=132

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galina1969 [7]

Answer:

Green graph: y = 5x + 2

Red Graph: y = 3x + 3

Blue graph: y = 2x + 3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the value of x ​
AveGali [126]

Answer:

x = 120

Step-by-step explanation:

Since they are supplementary, they add up to 180 degrees.

So, you can say x + x/2 = 180

Then, you would solve it like an algebra problem.

Multiply both sides by 2

2x + x = 360

Simplify

3x = 360

Divide both sides by 3

x = 120

8 0
2 years ago
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 29 ft/s. Its height
Ilia_Sergeevich [38]

Answer:

\overline{v}_{@\Delta t=0.01s}=-15.22ft/s, \overline{v}_{@\Delta t=0.005s}=-15.11ft/s, \overline{v}_{@\Delta t=0.002s}=-15.044ft/s, \overline{v}_{@\Delta t=0.001s}=-15.022ft/s

Step-by-step explanation:

Now, in order to solve this problem, we need to use the average velocity formula:

\overline{v}=\frac{y_{f}-y_{0}}{t_{f}-t_{0}}

From this point on, you have two possibilities, either you find each individual y_{f}, y_{0}, t_{f}, t_{0} and input them into the formula, or you find a formula you can use to directly input the change of times. I'll take the second approach.

We know that:

t_{f}-t_{0}=\Delta t

and we also know that:

t_{f}=t_{0}+\Delta t

in order to find the final position, we can substitute this final time into the function, so we get:

y_{f}=29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}

so we can rewrite our formula as:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-y_{0}}{\Delta t}

y_{0} will always be the same, so we can start by calculating that, we take the provided function ans evaluate it for t=1s, so we get:

y_{0}=29t-22t^{2}

y_{0}=29(1)-22(1)^{2}

y_{0}=7ft

we can substitute it into our average velocity equation:

\overline{v}=\frac{29(t_{0}+\Delta t)-22(t_{0}+\Delta t)^{2}-7}{\Delta t}

and we also know that the initil time will always be 1, so we can substitute it as well.

\overline{v}=\frac{29(1+\Delta t)-22(1+\Delta t)^{2}-7}{\Delta t}

so we can now simplify our formula by expanding the numerator:

\overline{v}=\frac{29+29\Delta t-22(1+2\Delta t+\Delta t^{2})-7}{\Delta t}

\overline{v}=\frac{29+29\Delta t-22-44\Delta t-22\Delta t^{2}-7}{\Delta t}

we can now simplify this to:

\overline{v}=\frac{-15\Delta t-22\Delta t^{2}}{\Delta t}

Now we can factor Δt to get:

\overline{v}=\frac{\Delta t(-15-22\Delta t)}{\Delta t}

and simplify

\overline{v}=-15-22\Delta t

Which is the equation that will represent the average speed of the ball. So now we can substitute each period into our equation so we get:

\overline{v}_{@\Delta t=0.01s}=-15-22(0.01)=-15.22ft/s

\overline{v}_{@\Delta t=0.005s}=-15-22(0.005)=-15.11ft/s

\overline{v}_{@\Delta t=0.002s}=-15-22(0.002)=-15.044ft/s

\overline{v}_{@\Delta t=0.001s}=-15-22(0.001)=-15.022ft/s

5 0
3 years ago
In ΔQRS, the measure of ∠S=90°, the measure of ∠R=31°, and QR = 46 feet. Find the length of SQ to the nearest tenth of a foot.
ss7ja [257]

Answer:

SQ=23.7\ ft

Step-by-step explanation:

we know that

In the right triangle QRS

sin(R)=\frac{SQ}{QR} ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

sin(31^o)=\frac{SQ}{46}

solve for SQ

SQ=\frac{SQ}{46}sin(31^o)=23.7\ ft

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3 years ago
How many 3/4 cup servings are there in 8 cups of berries?
sweet-ann [11.9K]
Your answer is A. 10 2/3. 
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