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2 years ago

If 8y-8=24 find the value of 2y

Mathematics

2 answers:

Aloiza [94]2 years ago

4 0

Answer:

Step-by-step explanation:

8y-8=24

+8 +8

8y=32

32/8 = 4

y=4

4*2=8

icang [17]2 years ago

3 0

Answer:

Step-by-step explanation:

8 y - 8 = 24

( + 8 )

8 y = 32

( ÷ 4 )

y = 4

Find the value of 2 y

y = 4 so 2 y = 8

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What is the y-intercept of the graphed linear function? (0, –8) (0, –2) (0, 2) (0, 4)

koban [17]

Answer:

All of them

Step-by-step explanation:

A y-intercept is the point where a line or curve crosses the y-axis of a graph. Example: (0, 7) (0, 6)

6 0

3 years ago

Read 2 more answers

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago

A store sells cans of tomatoes priced as shown.

lesantik [10]

Answer:

The answer is C. 18 ounces

Step-by-step explanation:

You just divide the ounces by the cost and which ever you get lower is the answer

3 0

3 years ago

ALGEBRA NATION!!! NEED HELP :(

Vilka [71]

Length of AC is 5 I hope this helps I can’t think right right now so bare with me

6 0

3 years ago

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kotykmax [81]

Answer:

3)n×x^n-1

Step-by-step explanation:

3 0

2 years ago