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dalvyx [7]
3 years ago
14

dale has $25 to spend at a carnival. if the admission to the carnival is $5 and the rides cost $1.50 each, what is the greatest

number of rides dale can afford
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
5 0
$25-5=20
20÷ 1.50=13.333333333
Round off the answer and you get 13

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Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

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(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

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3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

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hope this helps!

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