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dlinn [17]
3 years ago
15

Martin is studying sucrase activity. He added sucrose solution + sucrase solution + buffer of pH 5.6 in two tubes. He incubated

them at 350C and 1000C respectively. When he performed a confirmatory test, only the first test tube showed enzyme activity. How would you justify the inactivity of the enzyme in the second test tube?
Biology
1 answer:
Gre4nikov [31]3 years ago
5 0

I assume that second tube is under 100 degree celcius incubation. In the second tube case, the temperature is too high for the enzyme to properly functioning and most of cellular activities at this temperature will normally stop because the temperature is exceeding their maximum thermo threshold.

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5 0
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Someone please help!
ASHA 777 [7]

1.

a.  Bb

b. bb

c. Gray, because the male is homozygous recessive, which indicates the recessive trait is black.

d.  Gray-Female, Black-Male

e.      B       b

    b  Bb     bb

    b  Bb    bb

f.  There's a 50% chance the babies will be heterozygous (for gray) and there's a 50% chance the babies will be homozygous recessive for black.

g. There's a chance that all four offspring won't adhere exactly to the ratios predicted by the Punnett Squares, because male offspring can only have one trait (on the X).


Hope this helps. I hope you understand that heterozygous is (Big Letter & Small letter) and homozygous is either: Big Letter Big Letter OR Small Letter Small Letter. Have a great night and I hope you are successful in your class!


3 0
3 years ago
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