Answer:
1. DLL Files.
2. System software repair.
3. Software configuration.
4. Human-computer interaction.
5. A graphical user interface (GUI).
Explanation:
1. DLL Files can become lost or damaged on a computer and prevent it from working correctly. These are important registry files used by various system softwares to perform specific tasks.
2. System software repair is a type of software you can run to help fix computer problems. Some examples are disk defragmenter, regedit, etc.
3. Software configuration means the process of setting up an application and selecting specific options. This is usually done in the settings section of a software application or program.
4. Human-computer interaction is the name of the discipline concerned with the design of optimal user interfaces.
5. A graphical user interface (GUI) is what users make use of to interact with graphical icons and other visual elements in order to accomplish tasks.
Answer:
Key escrow.
Explanation:
If a full disk encryption (FDE) password is forgotten, a key escrow can be incorporated to securely store the encryption key to unlock the disk.
A key escrow can be defined as a data security method of storing very essential cryptographic keys.
Simply stated, key escrow involves a user entrusting his or her cryptographic key to a third party for storage.
As a standard, each cryptographic key stored or kept in an escrow system are directly linked to the respective users and are encrypted in order to prevent breach, theft or unauthorized access.
Hence, the cryptographic keys kept in an escrow system are protected and would not be released to anyone other than the original user (owner).
<em>Therefore, when a full disk encryption (FDE) password is forgotten, a key escrow if incorporated can be used to retrieve the password. Subsequently, the password would then be used to unlock or decrypt the disk.</em>
Answer:
Consider the following code.
Explanation:
save the following code in read_and_interp.m
function X = read_and_interp(s)
[m, n] = size(s);
X = zeros(m, 1);
for i = 1:m
if(str2num(s(i, 2:5)) == 9999)
% compute value based on previous and next entries in s array
% s(i, 2:5) retrieves columns 2-5 in ith row
X(i,1) = (str2num(s(i-1 ,2:5)) + str2num(s(i+1,2:5)))/2;
else
X(i,1) = str2num(s(i,2:5));
end
end
end
======================
Now you can use teh function as shown below
s = [ 'A' '0096' ; 'B' '0114' ; 'C' '9999' ; 'D' '0105' ; 'E' '0112' ];
read_and_interp(s)
output
ans =
96.000
114.000
109.500
105.000
112.000
Medicare because it’s like insurance
A already assigned variable cannot be assigned twice You can make the variable change over to a new one or call a whole new one to assign one without a value or It might be possible to do v=n (v is variable and n is number / value)
