We are given triangles QRS and DEF.
QR = DE and SR = FE.
Also we are given angle < R = 62 degrees and angle < E = 50 degrees.
<R is greater than the < E.
Note: Corresponding side of smaller angle is small.
<em>In triangle QRS, < R is greater angle than the <E in triangle DEF.</em>
Therefore, side DF is smaller side of QS.
<h3>Therefore, correct statement is B. DF < QS .</h3>
Answer: (A)
Step by Step
9/2 is rise over run so your 9 would be on the y axis representing the height and your 2 would be on the x axis representing age(yrs)
Let Fn be the number of ways of arranging such flagpole with the given conditions.
When arranging a flagpole of n feet high, consider the following cases
If the last flag used is a red flag, then the other flags are n-1 foot high, so they can be seen as arranged on a smaller flagpole of n-1 feet high, which can be done in Fn-1 ways.
Similarly, If the last flag used is a gold flag, then the other flags can be seen as arranged on a smaller flagpole of n-1 feet high. This can be done in Fn-1 ways.
If the last flag used is green, the other flags are n-2 feet high, so the flagpole can be arranged in Fn-2 ways.
Using the sum rule, we obtain that Fn = 2Fn-1 + Fn-2 for all n≥3. Listing all the combinations of flags, the initial conditions are F1 = 2 and F2 = 3.
To Learn more about similar flagpole questions:
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-0.425 and to get that you divide 17 by 40 hope this helps you
ANY PART OF THE PAPER AS LONG AS THEY COLOR 1/4 OF THE PAPER