Ask question

Ask question

All categories

3 years ago

10

Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?

1 answer:

serg [7]3 years ago

8 0

Can i please get the equation so i can solve it

I will edit this after you put it

Ignore this \/

Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28

Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?

You might be interested in

Select the correct answer from each drop-down menu.

Elodia [21]

Answer:

The left end approaches to + Infinite being an exponential function, and the right end to 0

Step-by-step explanation:

we have to remember the exponential function, the best way to find the answer is plotting the graph or arranging a table of values.

As you can see in the attached graph the y axis gets closer and closer to 0 as it moves forward in the x axis, and as it moves to the left the y axis starts increasing rapidly.

Also you got to keep in mind the way that functions behave in terms of the sign of its variable. for example the 10 in this equation only makes the curve to get wider, but if you change the sign to minus, the answer would be different.

8 0

3 years ago

Simplify the following expression<br> by combining like terms.<br> 3b + 8 – 3- b = 2b + [?]

babymother [125]

The missing term is 5

3 0

3 years ago

Two marathon runners run the full distance of the marathon, approximately 26 miles, in 4 hours.

xxTIMURxx [149]

Answer:

6.5 miles in 1 hour and they will run 75% of the full distance in 1 hour.

Step-by-step explanation:

The distance covered by two marathon runners = 26 miles

They takes 4 hours

We need to find how many miles did they run in 1 hour

In 4 hour, the distance covered is 26 miles

To find distance covered in 1 hour, divide 26 by 4 such that.

$d=\dfrac{26}{4}\\\\d=6.5\ \text{miles/hour}$

So, they will cover 6.5 miles in 1 hour.

For percentage,

$\%=\dfrac{26-6.5}{26}\times 100\\\\=75\%$

So, they will run 75% of the full distance in 1 hour.

8 0

3 years ago

A randomly generated list of integers from 0 to 4 is being used to simulate an event, with the numbers 1, 2, and 3 representing

Tresset [83]

Answer:

I think the anwser is

<h2>C.60 percent</h2>

hope it helped

6 0

3 years ago

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

6 0

3 years ago

Read 2 more answers