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3 years ago

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Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?

1 answer:

serg [7]3 years ago

8 0

Can i please get the equation so i can solve it

I will edit this after you put it

Ignore this \/

Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28

Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?Under a dilation with center P and scale factor k, A' is the image of A. What is the value of k if PA = 7, and PA' = 28?

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Please please please helpppp, (please show work if you can)

____ [38]

Answer:

∴ m∠KIJ = 18° and m∠HIJ = 50°

Thus, option a is correct.

Step-by-step explanation:

From the figure, it is clear that:

m∠KIH = m∠HIJ + m∠KIJ

Given

m∠KIH = 68°

m∠KIJ = (2x + 6)°

m∠HIJ = (9x - 4)°

now substituting m∠KIH = 68°, m∠KIJ = (2x + 6)° and m∠HIJ = (9x - 4)° in the equation

m∠KIH = m∠HIJ + m∠KIJ

68° = (2x + 6)° + (9x - 4)°

switch sides

$\left(2x+6\right)+\left(9x-4\right)=68$

Group like terms

$2x+9x+6-4=68$

$11x+2=68$

Subtract 2 from both sides

$11x+2-2=68-2$

Simplify

$11x=66$

Divide both sides by 11

$\frac{11x}{11}=\frac{66}{11}$

Simplify

$x=6$

Hence, the value of x = 6

Therefore,

m∠KIJ = (2x + 6)° = 2(6) + 6 = 12 + 6 = 18°

m∠HIJ = (9x - 4)° = 9(6) - 4 = 54 - 4 = 50°

∴ m∠KIJ = 18° and m∠HIJ = 50°

Thus, option a is correct.

8 0

2 years ago

Each day valerie charges her lunch account for her lunch. If the cost of lunch is $3 then by how much has her lunch account been

gavmur [86]

Answer: the amount by which her lunch account would have been impacted is $45

Step-by-step explanation:

Each day Valerie charges her lunch account for her lunch. If the cost of lunch is $3 then, it means that Valerie charges the lunch account with $3 daily. It means that in x days, she would have charged her lunch account with 3×x = $3x

If she charged her account for a period of 15 days, it means that x = 15. Therefore, the amount by which her lunch account would have been impacted is 3×15 = $45

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2 years ago

A party size bag of tortilla chips normally costs 3.80. The supermarket has them on sale today for 2.85.what is the percentage o

3241004551 [841]

The percentage of the discount is 75%

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3 years ago

Read 2 more answers

Write the point-slope form of the equation of the line through the given point woth the given slope

Andrej [43]

Answer:

3.) $\displaystyle y - 4 = 4[x - 1]$

2.) $\displaystyle y + 5 = 2[x + 2]$

1.) $\displaystyle y + 3 = 1\frac{1}{5}[x + 5]$

Step-by-step explanation:

In the Point-Slope Formula, $\displaystyle y - y_1 = m[x - x_1],$ all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.

* $\displaystyle 1\frac{1}{5} = \frac{6}{5}$

I am joyous to assist you anytime.

3 0

2 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

2 years ago