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3 years ago

15

the scale on a map se oanchows 5 centimeters equals 2 kilometers what nuumber of centimeters on the map represents an actual dis

tance of 5 kilometers

1 answer:

Igoryamba3 years ago

8 0

12.5 cm equals 5 km.

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How can you write 52+(8+25) to make it easier to add?

Liono4ka [1.6K]

You can't really make it easier to add, but since the (8+25) is in parentheses you should add that first

52 + 33

Then add straight away

52 + (8+25) = 85

8 0

3 years ago

Read 2 more answers

Translate the phrase "in 3 years" into algebraic terms

Semenov [28]

Answer:

In three years can be into algebraic terms as: 3 + x. Where 'x' comes to be today's age.

For example, my age in three years will be:

If I'm 24 years right now, My age in three years = 3 + x ⇒ My age in three years = 3 + 24 = 27.

3 0

3 years ago

Simplify the expression. Write your answer using only positive exponents. Evaluate any numerical powers.

gtnhenbr [62]

Answer:

9x⁵

Step-by-step explanation:

<u>Use properties of exponents:</u>

<u /> $a^{b} a^{c} = a^{b+c}$ , $(a^{b} ^)^{c} = a^{bc}$ , $1/a^{-b} = a^{b}$

<u>Simplify the given expression:</u>

3⁴⋅x⋅(3/x²)⁻² =
3⁴·x·(3x⁻²)⁻² =
3⁴·x·(3⁻²)(x⁻²ˣ⁻²) =
3⁴⁻²·x¹⁺4 =
3²·x⁵ =
9x⁵

5 0

3 years ago

Solve for x. Enter your answer below as a fraction in lowest terms, using the

Eddi Din [679]

Answer:

x = $\frac{9}{80}$

Step-by-step explanation:

Given

x + $\frac{9}{20}$ = $\frac{9}{16}$

Multiply through by 80 ( the LCM of 20 and 16 ) to clear the fractions

80x + 36 = 45 ( subtract 36 from both sides )

80x = 9 ( divide both sides by 80 )

x = $\frac{9}{80}$

8 0

3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$

$du=dx$ $v=2\cdot{e^(2x)}$

$\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du$

$\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx$

$\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C$

We can therefore determine that if x tends to 0 the limit is -1

$\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1$

5 0

3 years ago