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3 years ago

What is 15 divided by 1634

Mathematics

2 answers:

valina [46]3 years ago

5 0

The answer is 108.93

Mazyrski [523]3 years ago

3 0

Answer:108.93 repeating

Step-by-step explanation:

1634/15

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Solve the given equation for x. 8-6/5x=10

Elanso [62]

Answer:

x = -5/3

-1.667

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

2² + 5 • 4 ÷ 2 =? is it 18 or 14, and how? this is for my own personal studying

Mrac [35]

The answer is 14 because

4 divided by 2 is 2 multipled by 5 = 10 that exponet on the base of 2 equals four and 4+10=14

7 0

3 years ago

Do it please..............h

katrin [286]

Answer:

False

Step-by-step explanation:

-x^2+x is the same as x-x^2.

Only difference is the way it's written.

8 0

3 years ago

Read 2 more answers

According to Nielsen Media Research. of all the U.S. households that owned at least one television set, 83% had two or more sets

Rudik [331]

Answer:

The proportion of U.S. households that owned two or more televisions is 83%.

Step-by-step explanation:

To determine whether the proportions of U.S. households that owned two or more televisions is less than 83% or not let us perform a hypothesis test for single proportion.

Assumptions:

The sample size (n) selected by the local cable company is 300 which is quite large. Then according to the Central limit theorem the sampling distribution of sample proportion follows a normal distribution with mean p and standard deviation $\sqrt{\frac{p(1-p)}{n} }$ .

Since the sampling distribution of sample proportions follows a normal distribution use the z-test for one proportion to perform the test.

The hypothesis is:

$H_{0}$ : The proportion of U.S. households that owned two or more televisions is 83%, i.e. $p=0.83$

$H_{1}$ :The proportion of U.S. households that owned two or more televisions is less than 83%, i.e. $p< 0.83$

Decision Rule:

At the level of significance α = 0.05 the critical region for a one-tailed z-test is:

$\\ Z\leq -1.645\\$

**Use the z table for the critical values.

So, if $\\ Z\leq -1.645\\$ the null hypothesis will be rejected.

Test statistic value:

$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

Here $\hat{p}$ is the sample proportion.

Compute the value of $\hat{p}$ as follows:

$\hat{p}=\frac{X}{n} \\=\frac{240}{300}\\ =0.80$

Now compute the value of the test statistic as follows:

$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}\\=\frac{0.80-0.83}{\sqrt{\frac{0.83*(1-0.83)}{300} } } \\=-1.383$

The test statistic is -1.383 which is more than -1.645.

Thus, the test statistic lies in the acceptance region.

Hence we fail to reject the null hypothesis.

Conclusion:

At 0.05 level of significance we fail to reject the null hypothesis stating that the proportion of U.S. households that owned two or more televisions is 83%.

6 0

3 years ago

A large wooden box, as shown, has a volume of 4352 ft3. The box is a right square prism with a base with sides that each measure

notsponge [240]

<h2>Volume of a Prism</h2>

To find the volume of a prism, we can use the following formula:

$V=base\hspace{3}area*height$

Although this formula is typically used to find the volume of a prism, we can also use it to find the base area or height, as long as we re-arrange it accordingly.

For a rectangular prism, the base area is solved using the following formula:

$A=lw$ ⇒ where l is the length and w is the width

<h2>Solving the Question</h2>

We're given:

V = 4352 ft³
l = 16 ft
w = 16 ft
We need to solve for the height of the box.

First, find the base area:

$A=lw\\A=16^2\\A=256$

Therefore, the base area is equal to 256 ft².

Now, modify the volume formula to isolate the height:

$V=base\hspace{3}area*height$

⇒ Divide both sides by the base area:

$\dfrac{V}{base\hspace{3}area}=\dfrac{base\hspace{3}area*height}{base\hspace{3}area}\\\\\dfrac{V}{base\hspace{3}area}=height\\\\height=\dfrac{V}{base\hspace{3}area}$

⇒ Plug in the given values:

$height=\dfrac{4352}{256}\\\\height=17$

Therefore, the height of the box is 17 ft.

<h2>Answer</h2>

The height of the box is 17 ft.

3 0

2 years ago