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Varvara68 [4.7K]
3 years ago
8

Factor completely 6w^4 – 54w^2

Mathematics
2 answers:
kondaur [170]3 years ago
5 0
6w^4-54w^2=6w^2\cdot w^2-6w^2\cdot9=6w^2\cdot(w^2-9)=6w^2(w-3)(w+3)
MaRussiya [10]3 years ago
4 0
6w^4-54w^2=6w^2(w^2-9)=6w^2(w^2-3^2)=6w^2(w-3)(w+3)
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Is anyone willing to help me with this? I tried adding this and still no answer. Please help..
GaryK [48]

Answer:   C. (-4, -2)

<u>Step-by-step explanation:</u>

First, eliminate one of the variables and solve for the remaining variable:

2x - 5y = 2      →    3(2x - 5y = 2)      →     6x - 15y = 6

3x + 2y = -16   →  -2(3x + 2y = -16)    →  <u> -6x - 4y = 32</u>

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Next, replace "y" with -2 into either of the original equations to solve for x:

2x - 5y = 2

2x - 5(-2) = 2

2x + 10 = 2

2x         = -8

 x          = -4

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<u>Check:</u>

Plug in the x- and y-values into the other original equation:

3x + 2y = -16

3(-4) + 2(-2) = -16

-12  +  -4     = -16

      -16         = -16   \checkmark

3 0
3 years ago
In math class, you have the following scores: 77, 82, and 73. If the
ziro4ka [17]

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6 0
3 years ago
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