Factor completely 6w^4 – 54w^2

Mathematics

2 answers:

kondaur [170]3 years ago

5 0

$6w^4-54w^2=6w^2\cdot w^2-6w^2\cdot9=6w^2\cdot(w^2-9)=6w^2(w-3)(w+3)$

MaRussiya [10]3 years ago

4 0

$6w^4-54w^2=6w^2(w^2-9)=6w^2(w^2-3^2)=6w^2(w-3)(w+3)$

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