The length of the pole is 19.15 feet.
<h3>What is the angle of elevation?</h3>
The angle of elevation is the angle created when an observer looks at an object placed above its height in relation to the eye level or the horizontal line. An angle of elevation is, for example, the angle created between the line of sight and the horizontal line when a man on Earth observes the Sun.
Given:
Angle made by straight road = 15°
Angle of elevation of the sun = 57°
Length of the shadow = 75 feet
∠ACB = 90° - 57° = 33°
∠CAB = 57° - 15° = 42°
Using Sine Law to find BC i.e.length of the pole.



BC ≅ 19.15 feet (to the nearest hundredth.)
Hence, the approximate length of the pole is 19.15 feet.
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Answer:
C. ![\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-24%260%26-3%5C%5C8%26-48%2656%5C%5C25%26-6%2610%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The given matrices are;
and
![C=\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]](https://tex.z-dn.net/?f=C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%26%5Cfrac%7B3%7D%7B2%7D%5C%5C1%26-6%267%5Cend%7Barray%7D%5Cright%5D)
![FC=\left[\begin{array}{cc}-2&0\\0&8\\2&1\end{array}\right]\left[\begin{array}{ccc}12&0&\frac{3}{2}\\1&-6&7\end{array}\right]](https://tex.z-dn.net/?f=FC%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%260%5C%5C0%268%5C%5C2%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%260%26%5Cfrac%7B3%7D%7B2%7D%5C%5C1%26-6%267%5Cend%7Barray%7D%5Cright%5D)
![FC=\left[\begin{array}{ccc}12(-2)+0(1)&0(-2)+-6(0)&\frac{3}{2}(-2)+7(0)\\12(0)+8(1)&0(0)+8(-6)&0(\frac{3}{2})+8(7)\\2(12)+1(1)&2(0)+1(-6)&2(\frac{3}{2})+1(7)\end{array}\right]](https://tex.z-dn.net/?f=FC%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%28-2%29%2B0%281%29%260%28-2%29%2B-6%280%29%26%5Cfrac%7B3%7D%7B2%7D%28-2%29%2B7%280%29%5C%5C12%280%29%2B8%281%29%260%280%29%2B8%28-6%29%260%28%5Cfrac%7B3%7D%7B2%7D%29%2B8%287%29%5C%5C2%2812%29%2B1%281%29%262%280%29%2B1%28-6%29%262%28%5Cfrac%7B3%7D%7B2%7D%29%2B1%287%29%5Cend%7Barray%7D%5Cright%5D)
This simplifies to;
![FC=\left[\begin{array}{ccc}-24&0&-3\\8&-48&56\\25&-6&10\end{array}\right]](https://tex.z-dn.net/?f=FC%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-24%260%26-3%5C%5C8%26-48%2656%5C%5C25%26-6%2610%5Cend%7Barray%7D%5Cright%5D)
The correct answer is C
6 meters, both mm and cm are too small to be reasonable, as lakes are deep enough to have boats on and to swim in.
Answer:
302in cubed
Step-by-step explanation:
equation 2(5x11+6x11+5x6)