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Olin [163]
3 years ago
10

6. Use the data to find the following (Please show work)

Mathematics
1 answer:
Pani-rosa [81]3 years ago
4 0

Answer:

1. \boxed{ \boxed{ \sf{mean = 10}}}

2. \boxed{ \boxed{ \sf{median = 10.5}}}

3. \boxed{ \boxed{ \sf{mode = 11}}}

4. \boxed{ \boxed{ \sf{range = 16}}}

Step-by-step explanation:

1. Given data : 2 , 3 , 5 , 7 , 8 , 10 , 11 , 11 , 13 , 15 , 17 , 18

Σx = 2 + 3 + 5 + 7 + 8 + 10 + 11 + 11 + 13 + 15 + 17 + 18 = 120

N ( total number of items ) = 12

<u>Finding</u><u> </u><u>the</u><u> </u><u>mean</u>

To find the mean, divide the sum of all the items by the number of items.

\boxed{ \sf{mean =  \frac{Σx}{N} }}

\dashrightarrow{ \sf{mean =  \frac{120}{12} }}

\dashrightarrow{ \sf{mean = 10}}

Mean = 10

----------------------------------------------------------

2. Given data : 2 , 3 , 5 , 7 , 8 , 10 , 11 , 11 , 13 , 15 , 17 , 18

N ( total number of items ) = 12

<u>Finding</u><u> </u><u>the</u><u> </u><u>position </u><u>of </u><u>median</u>

\boxed{ \sf{median =   { \frac{n + 1}{2} }^{th \: item}}}

\dashrightarrow{ \sf{median =  {( \frac{12 + 1}{2}) }^{th \: } item}}

\dashrightarrow{ \sf{median =  {( \frac{13}{2}) }^{th \: }item }}

\dashrightarrow{ \sf{median =  {6.5}^{th \: }}} item

\sf{ {6.5}^{th} } item is the average of 6 th and 7 th items.

\sf{∴ \: median =  \frac{ {6}^{th}item +  {7}^{th}  item}{2}}

\dashrightarrow{ \sf{median =  \frac{10 + 11}{2} }}

\dashrightarrow{ \sf{median =  \frac{21}{2} }}

\dashrightarrow{ \sf{median = 10.5}}

Median = 10.5

-----------------------------------------------------------

3. The mode of a set of data is the value with the highest frequency.

Given data : 2, 3, 5, 7, 8, 10, 11, 11, 13, 15, 17, 18

Here, 11 has the highest frequency.

So, Mode = 11

----------------------------------------------------------

4. Highest number = 18

Lowest number = 2

\boxed{  \sf{range = highest \: number - lowest \: number}}

\dashrightarrow{ \sf{range = 18 - 2}}

\dashrightarrow{ \sf{range = 16}}

Hope I helped!

Best regards! :D

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Answer:

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