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3 years ago

Name two 2 digit factors whose product is greater than 200 but less than 600

Mathematics

2 answers:

myrzilka [38]3 years ago

7 0

My answer is two times one-hundred and one

Alexxandr [17]3 years ago

3 0

10 and 21, 10*21=210

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PLEASE HELP FOR A COOKIE

nikdorinn [45]

Create a ratio and cross multiply

20x - 75 = 14x + 63
6x = 138
x=23

hope this helps :)

6 0

3 years ago

Eight less than the product of seven x

lisabon 2012 [21]

Answer:

2x - 8

Step-by-step explanation:

Product of two and a number x

⇒ 2 multiply by x

⇒ 2x

Eight less than 2x

⇒ Take away 8 from 2x

⇒ 2x - 8

8 0

3 years ago

Read 2 more answers

If T(x, y) = (x + 5, y + 6) and Pris the image of P, what is the rule for the translation in which P is the image of P'? T(x, y)

xxTIMURxx [149]

Answer:

The translation is;

$T(x,y)=(x-5,y-6)$

Explanation:

Given the translation rule;

$T(x,y)=(x+5,y+6)$

when P' is the image of P.

For the inverse, when P is the image of P', the Translation rule would become;

$\begin{gathered} x=x^{\prime}+5 \\ x^{\prime}=x-5 \\ y=y^{\prime}+6 \\ y^{\prime}=y-6 \\ So,\text{ the translation rule becomes;} \\ T(x,y)=(x-5,y-6) \end{gathered}$

The translation is;

$T(x,y)=(x-5,y-6)$

3 0

10 months ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

Distributive Property (a+8)(a-3)=

polet [3.4K]

Distribute.

(a + 8)(a -3)

FOIL:

First, Outside, Inside, and Last

a * a = a^2

a * 3 = 3a

8 * a = 8a

8 * -3 = - 24

a^2 + 11a - 24

Distributed Expression: a^2 + 11a - 24

3 0

3 years ago