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Elan Coil [88]
3 years ago
9

If two lines intersect, then there is(are) _____ that contain(s) them. one point many points one plane many planes

Mathematics
2 answers:
marusya05 [52]3 years ago
8 0
The answer is one point.
klemol [59]3 years ago
4 0

Answer:

If two lines intersect, then there is one plane  that contain(s) them.

Step-by-step explanation:

If two lines intersect, then there is one plane  that contain(s) them.

If two points lie in a plane, then the line joining them lies in that plane. If two lines are intersecting, then exactly one plane contains both the lines.

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Simplify. −|11|=___<br> -11<br> -121<br> 121<br> 11
OleMash [197]

Assignment: \bold{Solve \ Equation: \ -\left|11\right|}

<><><><><><><>

Answer: \bold{-11}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

  • [ Step One ] Apply Absolute Rule
  • Note: \bold{Absolute \ Rule: \left|a\right|=a,\:a\ge 0}

\bold{\left|11\right|=11}

[ Step Two ] Simplify

\bold{-11}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

6 0
3 years ago
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Hellohello, if you able to help me then please do. (:
Alja [10]

Answer:

The answer is D.

Sum means addition. So, you would be adding a and b. Remember this; a - b = difference, a * b = product, a ÷ b = quotient, and a + b = sum. Good luck!

7 0
3 years ago
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What is the solution to the linear equation?<br><br> –12 + 3b – 1 = –5 – b
marysya [2.9K]
-12+3b-1=-5-b
Combine like terms to get:
3b-13=-5-b
Add 13 to both sides:
3b= 8-b
Add b to both sides:
4b=8
Divide both sides by 4:
4b/4=8/4
b=2

Final answer
b=2
4 0
3 years ago
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Please help me.
mart [117]

Since they are similar both dimensions would have the same ratio. The ratio of 5 and 15 is 3. 15 is 3 times larger than 5, so the unknown dimension is 3 times larger than the known dimension.

3 x 10 = 30

The unknown dimension is 30

5 0
3 years ago
How would you write this equation in terms of sin and cos as well as simplify it from there?
ziro4ka [17]
Try this option:
(1+ \frac{cosx}{sinx})(1- \frac{cosx}{sinx})- \frac{1}{sin^2x}= \frac{sin^2x-cos^2x}{sin^2x}- \frac{1}{sin^2x}=
= \frac{sin^2x-cos^2x-sin^2x-cos^2x}{sin^2x}=- \frac{2cos^2x}{sin^2x}.
or -2ctg²x
8 0
3 years ago
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