All categories

3 years ago

If two lines intersect, then there is(are) _____ that contain(s) them. one point many points one plane many planes

Mathematics

2 answers:

marusya05 [52]3 years ago

8 0

The answer is one point.

klemol [59]3 years ago

4 0

Answer:

If two lines intersect, then there is one plane that contain(s) them.

Step-by-step explanation:

If two lines intersect, then there is one plane that contain(s) them.

If two points lie in a plane, then the line joining them lies in that plane. If two lines are intersecting, then exactly one plane contains both the lines.

You might be interested in

Simplify. −|11|=___ -11 -121 121 11

OleMash [197]

Assignment: $\bold{Solve \ Equation: \ -\left|11\right|}$

<><><><><><><>

Answer: $\bold{-11}$

<><><><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><><><>

[ Step One ] Apply Absolute Rule
Note: $\bold{Absolute \ Rule: \left|a\right|=a,\:a\ge 0}$

$\bold{\left|11\right|=11}$

[ Step Two ] Simplify

$\bold{-11}$

<><><><><><><>

$\bold{\rightarrow Mordancy \leftarrow}$

6 0

3 years ago

Read 2 more answers

Hellohello, if you able to help me then please do. (:

Alja [10]

Answer:

The answer is D.

Sum means addition. So, you would be adding a and b. Remember this; a - b = difference, a * b = product, a ÷ b = quotient, and a + b = sum. Good luck!

7 0

3 years ago

Read 2 more answers

What is the solution to the linear equation? –12 + 3b – 1 = –5 – b

marysya [2.9K]

-12+3b-1=-5-b
Combine like terms to get:
3b-13=-5-b
Add 13 to both sides:
3b= 8-b
Add b to both sides:
4b=8
Divide both sides by 4:
4b/4=8/4
b=2

Final answer
b=2

4 0

3 years ago

Read 2 more answers

Please help me.

mart [117]

Since they are similar both dimensions would have the same ratio. The ratio of 5 and 15 is 3. 15 is 3 times larger than 5, so the unknown dimension is 3 times larger than the known dimension.

3 x 10 = 30

The unknown dimension is 30

5 0

3 years ago

How would you write this equation in terms of sin and cos as well as simplify it from there?

ziro4ka [17]

Try this option:
$(1+ \frac{cosx}{sinx})(1- \frac{cosx}{sinx})- \frac{1}{sin^2x}= \frac{sin^2x-cos^2x}{sin^2x}- \frac{1}{sin^2x}=$
$= \frac{sin^2x-cos^2x-sin^2x-cos^2x}{sin^2x}=- \frac{2cos^2x}{sin^2x}.$
or -2ctg²x

8 0

3 years ago