1/4. and. 1/12. will do that.
Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Step-by-step explanation:
You can use PEMDAS to solve this problem from left to right.
First, do 15 ÷ 3 to get 5.
Next, do 2 x 10 to get 20.
Lastly, add 5 and 20 to get 25.
<u>15 ÷ 3</u> + 2 x 10
5 + <u>2 x 10</u>
<u>5 + 20</u>
25
Answer:
a= (π/4) + (kπ/2)
Step-by-step explanation:
I have attached the explanation above. hopefully this will help
Answer:
$17.00
Step-by-step explanation:
10 x 1.70 = $17.00
