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Alecsey [184]
3 years ago
12

Please help me im not asking for much

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:Looooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooool

Step-by-step explanation:

Shalnov [3]3 years ago
5 0

Answer:

adding the two equations together

(1.5,8)

Step-by-step explanation:

8x=12

x=1.5

y=8

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What Is the area of a rectangular room that is 3 3/4 yards long and 3 1/3 yards wide
mr_godi [17]
9 1/4....................
7 0
3 years ago
on a map 2 centimeters represents 150 kilometers if a line between two cities measures 5 centimeters how many kilometer apart ar
SCORPION-xisa [38]

Answer:

375 kilometers

Step-by-step explanation:

1cm = 75kilometers(150÷2= 75)

2cm = 150kilometers

75×5= 375kilometers

5 0
3 years ago
Meg is recording all her expense (using negative numbers)and allowances.At the end of the month,she added her total allowances t
Ilya [14]

Answer:

<h2>Expenses= Allowance</h2>

Step-by-step explanation:

<em>The statements are not provided in the question, however, we can deduce from the information given.</em>

in the information provided, expenses are -ve(negative)

and allowances are +ve (positive)

if at the end of the month she balances are account and the total is zero

We can conclude that:

1. Her total expenses is equal to her allowance for the month

2. Meg spent all her allowances for the month

4 0
3 years ago
(a3 - 2a + 5) - (4a3 - 5a2 + a - 2)​
djverab [1.8K]

Answer:

5 * a^3 - 5 * a^2.

Step-by-step explanation:

is it wrong??

7 0
3 years ago
Read 2 more answers
Hence, write as single<br> frachon in its lowest terms.<br> 2/y-1 - 4/y^2-1
sleet_krkn [62]

Answer:

\frac{2}{y+1}

Step-by-step explanation:

Factorise the denominator of the second fraction

y² - 1 = (y - 1)(y + 1) ← difference of squares

To obtain a common denominator

multiply numerator/ denominator of first fraction by (y + 1)

= \frac{2(y+1)}{(y-1)(y+1)} - \frac{4}{(y-1)(y+1)} ← subtract numerators leaving the common denominator

= \frac{2y+2-4}{(y-1)(y+1)}

= \frac{2y-2}{(y-1)(y+1)}

= \frac{2(y-1)}{(y-1)(y+1)} ← cancel common factor (y - 1) on numerator/denominator

= \frac{2}{y+1}

6 0
3 years ago
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