Question

How do you completely factor 4k^2+14k+12?

Answer 1

2(2k+3)(k+2)
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Answer 2

Answer:

4k^2+14k+12 =(4k+6)(k+2)= 2(2k+3)(k+2)

Step-by-step explanation:

$4k^2+14k+12$

$4k^2+8k+6k+12$

$4k(k+2) + 6(k+2)$

(4k+6)(k+2)

2(2k+3)(k+2)is solution set