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3 years ago

5

Solve for xPlease help me

1 answer:

Taya2010 [7]3 years ago

5 0

Answer:

x = 9

Step-by-step explanation:

60 + 6x + 16 = 13x + 13

6x - 13x = 13 - 16 - 60

- 7x = - 63

- x = - 63/7

- x = - 9

x = 9

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Find f(-6) for f(x) = x² - 4x + 5. Be sure to show<br> your work.

Marina86 [1]

substitute $-6$ in the equation:

$f(x)=x^{2} -4x+5,\\f(-6)=(-6)^{2} -4(-6)+5\\f(-6)=36+24+5\\f(-6)=\boxed{65}$

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3 years ago

What is a reasonable distance between two cities?

deff fn [24]

I don't know the exact calculation but...maybe about 56,789 miles? based on that between Syracuse to California is 9,345 miles but...it depends on witch two cites you're talking about

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3 years ago

I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

7.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

8.

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

user100 [1]

He needs to run with approximately 6429 for a distance of 9 km

<h3>How to determine the number of strides?</h3>

The given parameters are:

Length of stride = 1.4 m

Distance for marathon = 9 km

The number of strides needed is then calculated as:

Number of stride = Distance for marathon/Length of stride

Substitute the known values in the above equation

Number of stride = 9km/1.4m

Convert km to m

Number of stride = 9000m/1.4m

Evaluate the quotient

Number of stride = 6428.57143

Approximate the estimate

Number of stride = 6429

Hence, he needs to run with approximately 6429 for a distance of 9 km

Read more about quotients at:

brainly.com/question/8952483

#SPJ1

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2 years ago

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leva [86]

Answer: no

Step-by-step explanation:

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3 years ago