Answer:
1. 73
2.-63
Step-by-step explanation:
1. 30+43=73
2. -84+21= 21-84=-63
Answer:
Time = 3secs
Max height = 56m
Step-by-step explanation:
Given the height reached by the rocket modeled by the equation;
h(x) = -5(x - 3)² + 56 where;
x is in seconds
The rocket velocity at its maximum height is zero.
Hence dh/dx = 0
dh/dx = 2(-5)(x-3)
dh/dx = -10(x-3)
Since dh/dx = 0
0 = -10(x-3)
0 = -10x + 30
10x = 30
x = 3secs
<em>Hence it takes 3 secs to reach the maximum height.</em>
Get the maximum height reached by the rocket. Substitute x = 3 into the equation given;
Recall that:
h(x) = -5(x - 3)² + 56
If x = 3
h(3) = -5(3 - 3)² + 56
h(3) = 0 + 56
h(3) = 56
<em>Hence the maximum height that the rocket reaches is 56m</em>
Answer:
-4/9
Step-by-step explanation:
We first calculate the first bracket.
[2/3-(-4/9)]
= (2/3+4/9) (we cancel out the negatives)
= (6/9+4/9) (common denominator)
= 10/9
Then we convert -2 1/2 into an improper fraction.
-2 1/2
= -5/2
Finally we calculate the division by swapping the numerator and denominator of -5/2.
10/9 / -5/2
= 10/9 * -2/5
= -20/45
= -4/9 (simplify the terms)
Answer:
14
Step-by-step explanation:
44-9=35
35+77=122
122÷8=14
Answer:
x = 8√2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only]: Pythagorean Theorem: a² + b² = c²
Step-by-step explanation:
<u>Step 1: Define</u>
We are given a right triangle. We can use PT to solve for the missing length.
<u>Step 2: Identify Variables</u>
Leg <em>a</em> = 8
Leg <em>b</em> = 8
Hypotenuse <em>c</em> = <em>x</em>
<u>Step 3: Solve for </u><em><u>x</u></em>
- Substitute [PT]: 8² + 8² = x²
- Exponents: 64 + 64 = x²
- Add: 128 = x²
- Isolate <em>x</em>: 8√2 = x
- Rewrite: x = 8√2
