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Mashutka [201]
3 years ago
8

Write a program that reads in 15 numbers in sorted order from the user (i.e. the user enters them in order) and stores them in a

1D array of size 15. Next, prompt the user for a number to search for in the array (i.e. the "target"). Then, print the array. Next, search the array using a linear search – printing out each of
Computers and Technology
1 answer:
photoshop1234 [79]3 years ago
3 0

Corrected Question

Write a program that reads in 15 numbers in sorted order from the user (i.e. the user enters them in order) and stores them in a 1D array of size 15. Next, prompt the user for a number to search for in the array (i.e. the "target"). Then, print the array. Next, search the array using a linear search – find the target element and printing out the target and its index as well as the entire array

Answer:

The solution is given in the explanation section

See detailed explanation of each step given as comments

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //Create the array of 15 elements

   int [] array = new int [15];

   //Create an object of the scanner class to receive user input

   Scanner in = new Scanner(System.in);

   //Prompt user to enter the values in sorted order

   //Using a for loop

   for (int i =0; i<array.length; i++){

         System.out.println("Enter the next element: In SORTED order please!");

         array[i] = in.nextInt();

   }

   System.out.println("All Fifteen element have been entered");

   // Ask the user for an element to be searched for

   //A target element

   System.out.println("Which element do you want to search for in the array");

   //Create the target element

   int target = in.nextInt();

   //Use a for loop to sequentially check each element in the array

   for(int i = 0; i<array.length; i++){

     if(array[i]==target){

       System.out.println(target+" is found at index "+i +" of the array");

     }

   }

       // Printout the entire array

   System.out.println(Arrays.toString(array));

 }

}

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